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Triss [41]
4 years ago
8

Need help on problems. Please Help!

Mathematics
1 answer:
Allushta [10]4 years ago
5 0

Answer:

I don't know, I'm so sorry, but can you respond at my question? Thanks

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Work out the third term of the sequence with nth term 3(n+2).<br><br>​
Anon25 [30]

Answer:

Step-by-step explanation:

n = 3

3(n + 2) = 3(3+2) = 3*5 = 15

6 0
3 years ago
Read 2 more answers
How many hours and minutes are there between 2:45 and 3:50?
Jlenok [28]
1 hour and 5 min. from 2:45 until 3:00 is 15 min. then from 3:00 until 3:50 is an additional 50 min. ad 15 and 50, and you get 65. every 60 min makes one hour, so that leaves you with one hour and five min.
3 0
4 years ago
given f(x)=2x^2 and g(x)=4x-5, the composition f(g(x)) is equal to 32x^2-80 x+53 now find an expression for g(f(x))
puteri [66]
F(x) is most likely the f(f(x)x) where f(x) is g(x))f)) and composition can be 69 + 46 which is the total of 137
5 0
3 years ago
Read 2 more answers
What is the nth term rule of the quadratic sequence below?
Vladimir [108]

Answer:

3n² + 5n - 2

Step-by-step explanation:

<u>Given sequence</u>:

6, 20, 40, 66, 98, 136, ...

Calculate the <u>first differences</u> between the terms:

6 \underset{+14}{\longrightarrow} 20 \underset{+20}{\longrightarrow} 40 \underset{+26}{\longrightarrow} 66 \underset{+32}{\longrightarrow} 98 \underset{+38}{\longrightarrow} 136

As the first differences are not the same, calculate the <u>second differences:</u>

14 \underset{+6}{\longrightarrow} 20 \underset{+6}{\longrightarrow} 26 \underset{+6}{\longrightarrow} 32 \underset{+6}{\longrightarrow} 38

As the <u>second differences are the same</u>, the sequence is quadratic and will contain an n² term.

The <u>coefficient</u> of the n² term is <u>half of the second difference</u>.

Therefore, the n² term is:  3n²

Compare 3n² with the given sequence:

\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2 & 3 & 12 & 27 & 48 \\\cline{1-5} \sf operation & +3&+8 & +13 & +18 \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}

The second operations are different, therefore calculate the differences <em>between</em> the second operations:

3 \underset{+5}{\longrightarrow} 8 \underset{+5}{\longrightarrow} 13\underset{+5}{\longrightarrow} 18

As the differences are the same, we need to add 5n as the second operation:

\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2  +5n & 8&22 & 42 & 68\\\cline{1-5}\sf operation & -2 &-2  &-2  & -2  \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}

Finally, we can clearly see that the operation to get from 3n² + 5n to the given sequence is to subtract 2.

Therefore, the nth term of the quadratic sequence is:

3n² + 5n - 2

6 0
2 years ago
i need help with a math problem right now it says A car rental agency advertised renting a car for $24.95 per day and $0.26 per
Dominik [7]

Answer:

He can drive 481 miles if David rents his car for three days

Step-by-step explanation:

This is true because if you take the 24.95 and multiply it by 3, because he rented it for three days, you'll get 74.85. Then you'll subtract 200 (the total money that can be spent) by 74.85 you'll get 125.15. Divide the remaining number, 125.15 by 0.26 to get 481.34. Take the decimals away because you don't need it, if you want to be sure it's correct you can multiply 481 by 0.26 to get 125.05 which is lower than 125.15 so it good because if you use 482 besides 481 it will be higher than the amount of money David can spend, that's why 481 is the right answer.

5 0
4 years ago
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