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Tcecarenko [31]
3 years ago
13

Which of the five measures of center (the mean, the median, the trimmed mean, the weighted mean, and the mode) can be calculated

for quantitative data only.
SAT
2 answers:
Anna007 [38]3 years ago
6 0
Quantitative data is defined as information that gives measurement or it can be written down in numbers.

<span>Each of these five measures of center 1) the mean, 2) the median, 3)the trimmed mean, 4) the weighted mean, and 5) the mode can be measured and written down in number. Thus, they are all quantitative data. 


</span>
Reptile [31]3 years ago
4 0
In Chapter 2 we discussed how to summarize data using different methods and to display data using graphs. Graphs are one important component of statistics; however it is also important to numerically describe the main characteristics of a data set. The numerical summary measures, such as the ones that identify the center and spread of a distribution, identify many important features of a distribution. For example, the techniques learned in Chapter 2 can help us graph data on family incomes. However, if we want to know the income of a “typical” family (given by the center of the distribution), the spread of the distribution of incomes, or the relative position of a family with a particular income, the numerical summary measures can provide more detailed information (see Figure 3.1). The measures that we discuss in this chapter include measures of (1) central tendency, (2) dispersion (or spread), and (3) position.
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How many electrons pass through a 20-ohms resistor in 10 min if there is a potential drop of 30 volts across it?
tangare [24]

The number of electrons passes through 20 ohms resistor in 10  minutes is 5.625e+21.

<h3>What is a resistor?</h3>

In an electronic circuit, a resistor is an electrical component that limits or regulates the flow of electrical current.

Given, the resistance is 20 ohms.

The potential difference is 30 volts

Time is 10 minute

By the formula of current

\rm I = \dfrac{30}{20} = 1.5 \;C/s

The charge flowing through the resistor is 1.5 C/s

1 electron charge is 1.6e+19

Now, the number of electrons passing through a 20 ohms resistor is

\dfrac{1.5}{1.6e+ ^2^1} = 0.9375e+^1^9

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Thus, the number of electrons passes through 20 ohms resistor in 10  minutes is 5.625e+21.

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