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OLEGan [10]
3 years ago
10

The trait of “freckles” is dominant and represented by A. No freckles is recessive and represented by a. A researcher crossed tw

o individuals, one homozygous dominant and the other heterozygous for freckles. Based on the data in the Punnett square, the researcher concluded that all offspring would have dominant as well as the recessive alleles. What comment would you make about his conclusion?
SAT
2 answers:
Ivahew [28]3 years ago
5 0

Answer:

It's wrong.

Explanation:

In the Punnett square, we will use F to represent the dominant freckles gene and f to represent the recessive lack-of-freckles gene. The first individual would have FF, because homozygous means that both alleles are the same. The second individual would have Ff, because heterozygous means that it has 2 different alleles. If the first individual passes down one of its "F" alleles and the second individual passes down its "F" allele, the offspring would have 2 dominant alleles, and the researcher's conclusion is disproven.

HACTEHA [7]3 years ago
5 0

Answer:

the possible solutions are AA, AA, Aa, Aa

The researchers conclusion is incorrect. Although the offspring all have dominant alleles, not all of them will have a recessive allele.

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<h3>pH of aniline solution</h3>

According to the question;

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Since, the given Kb is kb = 4. 3 × 10⁻¹⁰.

Hence, it follows that;

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