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4 years ago

Write an algebraic expression for the product of 15 and x

Mathematics

1 answer:

bezimeni [28]4 years ago

3 0

Answer:

15x is your answer. Hope this helps.

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What do I put next Please help

levacccp [35]

To divide fractions you flip the second one and then multiply the new fractions

9 16 9 5 45
--- ÷ ---- = ---- × ------ = ------
2 5 2 16 32

then simplify

45/32= 1 13/32

I hope I've helped!

4 0

4 years ago

An iceberg weighs 450,000 pounds if it loss 0.2% of its weight in a day, what is its new weight at the end of the day

marysya [2.9K]

Answer:

449 100

Step-by-step explanation:

0.2% × 450000÷ 100=900

450000-900= 449 100

5 0

3 years ago

Read 2 more answers

Which triangles are right triangles? Select all that apply.

Setler79 [48]

Answer:

triangle 1, triangle 3,

Step-by-step explanation:

Triangle 1= $14^{2} + 24^{2} = 772\\196+ 576 = 772$

Triangle 2= is wrong

Triangle 3= $11^{2} + 22^{2} = 605\\121+ 484= 605$

Triangle 4= is wrong.

7 0

3 years ago

The width of a container is 5 feet less than its height. Its length is 1 foot longer than its height. The volume of the containe

juin [17]

The height of container is 8 feet

Solution:

Let "w" be the width of container

Let "l" be the length of container

Let "h" be the height of container

The width of a container is 5 feet less than its height

Therefore,

width = height - 5

w = h - 5 ------ eqn 1

Its length is 1 foot longer than its height

length = 1 + height

l = 1 + h ---------- eqn 2

The volume of container is given as:

$v = length \times width \times height$

Given that volume of the container is 216 cubic feet

$216 = l \times w \times h$

Substitute eqn 1 and eqn 2 in above formula

$216 = (1 + h) \times (h-5) \times h\\\\216 = (h+h^2)(h-5)\\\\216 = h^2-5h+h^3-5h^2\\\\216 = h^3-4h^2-5h\\\\h^3-4h^2-5h-216 = 0$

Solve by factoring

$(h-8)(h^2+4h+27) = 0$

Use the zero factor principle

If ab = 0 then a = 0 or b = 0 ( or both a = 0 and b = 0)

Therefore,

$h - 8 = 0\\\\h = 8$

Also,

$h^2+4h+27 = 0$

Solve by quadratic equation formula

$\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

$\mathrm{For\:} a=1,\:b=4,\:c=27:\quad h=\frac{-4\pm \sqrt{4^2-4\cdot \:1\cdot \:27}}{2\cdot \:1}$

$h = \frac{-4+\sqrt{4^2-4\cdot \:1\cdot \:27}}{2}=\frac{-4+\sqrt{92}i}{2}$

Therefore, on solving we get,

$h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i$

Thus solutions of "h" are:

h = 8

$h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i$

"h" cannot be a imaginary value

Thus the solution is h = 8

Thus the height of container is 8 feet

8 0

3 years ago

Beinggreat78 please answer fast

alexdok [17]

The perimeter is 48 units

6 0

2 years ago

Read 2 more answers

Write an algebraic expression for the product of 15 and x​

Write an algebraic expression for the product of 15 and x