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klasskru [66]
2 years ago
8

2+2=?help I don't know​

Mathematics
1 answer:
ankoles [38]2 years ago
6 0

Answer:

4

Step-by-step explanation:

you and your friend got 2 slices of pizza each, how many do you have in total.

it would be four

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Make a table with the domain of {2,3,4,5,6} and draw a graph of the absolute value function y = 2|x-4| + 3.
Jet001 [13]

Answer:

<h2>In the attachment.</h2>

Step-by-step explanation:

|a|=\left\{\begin{array}{ccc}a&for\ a\geq0\\-a&for\ a

Put each value of x from the set {2, 3, 4, 5, 6}

to the equation y = 2|x - 4| + 3:

x = 2 → y = 2|2 - 4| + 3 = 2|-2| + 3 = 2(2) + 3 = 4 + 3 = 7 → (2, 7)

x = 3 → y = 2|3 - 4| + 3 = 2|-1| + 3 = 2(1) + 3 = 2 + 3 = 5 → (3, 5)

x = 4 → y = 2|4 - 4| + 3 = 2|0| + 3 = 2(0) + 3 = 0 + 3 = 3 → (4, 3)

x = 5 → y = 2|5 - 4| + 3 = 2|1| + 3 = 2(1) + 3 = 2 + 3 = 5 → (5, 5)

x = 6 → y = 2|6 - 4| + 3 = 2|2| + 3 = 2(2) + 3 = 4 + 3 = 7 → (6, 7)

Mark the points in the coordinates system.

The domain is only five numbers, therefore the graph of this function is only five points.

5 0
3 years ago
Read 2 more answers
A state is considering license plates that have two digits followed by four letters. Assuming no combinations are excluded, how
love history [14]

Answer:

32,292,000

Step-by-step explanation:

In your question, it asks how many license plate combinations we could make WITHOUT repeats.

We need some prior knowledge to answer this question.

We know that:

  • There are 26 letters in the alphabet
  • We can make 10 digits (0 - 9)

With the information we know above, we can solve the question.

Since we CAN'T have repeats, we would be excluding a letter or number for each license plate.

We're going to need to multiply each "section" in order to find how many combinations of license plates we can make.

We decrease by one letter and one number in each section since we can't have repeats.

Now, we can solve.

Work:

26*25*24*23*10*9 = 32,292,000

When you're done multiplying, you should get 32,292,000.

This means that there could be 32,292,000 different combinations of license plates.

<h3>I hope this helps you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>
8 0
3 years ago
Read 2 more answers
The probability of contamination in batch 1 of a drug (event A) is 0.16, and the probability of contamination in batch 2 of the
VLD [36.1K]
We have:
Event A ⇒ P(A) = 0.16
Event B ⇒ P(B) = 0.09
Probability of event B given event A happening, P(B|A) = P(A∩B) / P(A) = 0.12

By the conditional probability, the probability of event A and event B happens together is given by:
P(B|A) = P(A∩B) ÷ P(A)
P(B|A) = P(A∩B) ÷ 0.16
0.12 = P(A∩B) ÷ 0.16
P(A∩B) = 0.12 × 0.16
P(A∩B) = 0.0192

When two events are independent, P(A) × P(B) = P(A∩B) so if P(A∩B) = 0.0192, then P(B) will be 0.0192 ÷ 0.16 = 0.12 (which take us back to P(B|A))

Since P(B|A) does not equal to P(B), event A and event B are not independent.

Answer: <span>Events A and B are not independent because P(B|A) ≠ P(B)</span>

4 0
3 years ago
100 POINTS100 POINTS100 POINTS100 POINTS100 POINTS100 POINTS100 POINTS100 POINTS100 POINTS100 POINTS100 POINTS100 POINTS100 POIN
Viefleur [7K]
Hello!

There are only six was to to role a number less than four. 1 and 1. 1 and 2. 2 and 1. 1 and 3. 2 and 2. 3 and 3 and 1.

The first number on the die could be 1, and the second die could have a probability of rolling the second number on it. Giving us a probability of 1/6.

We can subtract the calculated probability from rolling less than four from 1 to find the probability of rolling more than 5:

1 - 1/6 = 5/6

So, your answer should be D 5/6.
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3 years ago
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I can't find the volume ​
sp2606 [1]

Answer:

8π(2.5)^2

Step-by-step explanation:

volume = π * r^2 * h

v = π * (2.5)^2 * 8

7 0
3 years ago
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