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3 years ago

The tax on a $400 painting is $34 what should be the tax on a $700 painting

Mathematics

2 answers:

pychu [463]3 years ago

8 0

The tax rounds up to $77.

MAXImum [283]3 years ago

4 0

$136 is the answer i think...

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Identify the number of terms in the expression. Type the answer in the space provided.

nadya68 [22]

Answer:

Step-by-step explanation:

Terms are separated from one another by + and/or - signs. In this case neither appears, so the given expression constitutes a single term.

3 0

3 years ago

find the circumference of the circle. d=23 in. a)144.44 in b)1661.06 in c)36.11 in d)72.22 in e)415.27 in

snow_lady [41]

Circumference of a circle = $\pi$ (diameter)

Diameter = 23 in.

Plug in the diameter = 23 in in the formula of circumference given above

Circumference of a circle = $\pi$ (23)

Circumference of a circle = 23 $\pi$

$\pi$ = 3.14

Circumference of a circle = 23 (3.14)

Circumference of a circle = 72.22 in

Option D is the answer

4 0

4 years ago

Read 2 more answers

Wes works at a science lab that conducts experiments on bacteria. The population of the bacteria multiplies at a constant rate,

Dmitry [639]

Answer:

Correct answer: at 2 p.m. the population was 10,000

at 3 p.m. the population was 50,000

Step-by-step explanation:

At 1 p.m. population was 2,000

At 2 p.m. or after first hour, the population of bacteria increases

in this way 2,000 · k

At 3 p.m. or after second hour, the population of bacteria increases

2,000 · k²

At 4 p.m. or after third hour, the population of bacteria increases 2,000 · k³

2,000 · k³ = 250,000 => k³ = 250,000 / 2,000 = 125

k = ∛125 = 5 => k = 5

At 2 p.m. or after first hour, the population of bacteria was 2,000 · 5 = 10,000

At 3 p.m. or after second hour, the population of bacteria was 2,000 · 5² =

= 2,000 · 25 = 50,000

God is with you!!!

6 0

3 years ago

a port and a radar station are 2 mi apart on a straight shore running east and west. a ship leaves the port at noon traveling no

Rom4ik [11]

Answer:

The rate of change of the tracking angle is 0.05599 rad/sec

Step-by-step explanation:

Here the ship is traveling at 15 mi/hr north east and

Port to Radar station = 2 miles

Distance traveled by the ship in 30 minutes = 0.5 * 15 = 7.5 miles

Therefore the ship, port and radar makes a triangle with sides

2, 7.5 and x

The value of x is gotten from cosine rule as follows

x² = 2² + 7.5² - 2*2*7.5*cos(45) = 39.04

x = 6.25 miles

By sine rule we have

$\frac{sin A}{a} = \frac{sin B}{b}$

Therefore,

$\frac{sin 45}{6.25} = \frac{sin \alpha }{7.5}$

α = Angle between radar and ship α

∴ α = 58.052

Where we put

$\frac{sin 45}{6.25} = \frac{sin \alpha }{x}$ to get

$\frac{x}{6.25} = \frac{sin \alpha }{sin 45}$ and differentiate to get

$\frac{\frac{dx}{dt} }{6.25} = cos\alpha\frac{\frac{d\alpha }{dt} }{sin 45}$

$\frac{15sin45 }{6.25cos\alpha } =\frac{d\alpha }{dt} }$ = 3.208 degrees/second = 0.05599 rad/sec.

6 0

3 years ago

Given fx) = 17- x2, what is the average rate of change in f(x) over the interval [1, 5]?

Andrei [34K]

Let [a, b] = the interval

The average rate of change can be found by using [f(b) - f(a)]/(b - a).

Let a = 1 and b = 5.

Let R = rate of change

17- x^2

R = [17 - 5^2] - [17 - 1^2]/(5 - 1)

R = [17 - 25] -[17 - 1]/4

R = [(-8) - (16)]/4

R = (-24)/4

R = -6

Done.

6 0

4 years ago

Read 2 more answers