Question

One number is equal to the square of another. find the numbers if both are positive and their sum is 18061806.

Answer 1

42, 1764 I am going to assume that there's a typo and the actual number is 1806. So we can create the following equalities: a = x^2 x + a = 1806 Since we know that a is x^2, we can substitute that, giving: x + x^2 = 1806 And finally, let make it into a normal quadratic equation: x^2 + x - 1806 = 0 Now using the quadratic formula, we can determine the roots to be x = -43 and x = 42. Since we've been told the numbers are positive, we'll select the value 42. Let's check our results "One number is equal to the square of another" 42*42 = 1764 "their sum is 1806" 42 + 1764 = 1806 So the 2 numbers we want are 42 and 1764