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3 years ago

11

Find the zeros of y=x^2-6x-4

1 answer:

Evgen [1.6K]3 years ago

4 0

X=3+√13, 3-√13

substitute y for 0 and solve for x

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Write 5/z^-3 as a positive exponent

levacccp [35]

The correct answer will be 5z^3

8 0

3 years ago

Solve. (x + 3)^1/2– 1 = x

Natali [406]

Answer:

x=1

Step-by-step explanation:

$(x + 3) ^{ \frac{1}{2} } - 1 = x \\ \sqrt{x + 3} - 1 = x \\ \sqrt{x + 3} = x + 1 \\ square \: both \: sides \\ x + 3 = {x}^{2} + 2x + 1 \\ {x}^{2} + 2x - x + 1 - 3 = 0 \\ {x}^{2} + x - 2 = 0 \\ x ^{2} + 2x - x - 2 = 0 \\ (x^{2} + 2x) - (x + 2) = 0 \\ x(x + 2) - 1( x + 2) = 0 \\ (x - 1)(x + 2) = 0 \\ x - 1 = 0 \\ x = 1 \\ \\ \\ x + 2 = 0 \\ x = - 2$

8 0

3 years ago

The length of a rectangle is 17 m and the width is 12 m what is the perimeter of the rectangle

lbvjy [14]

Answer:

<h2>The answer is 58 m</h2>

Step-by-step explanation:

Perimeter of a rectangle = 2l + 2w

where

l is the length

w is the width

From the question

length = 17 m

width = 12 m

Substitute the values into the above formula and solve for the perimeter

We have

Perimeter = 2(17) + 2(12)

= 34 + 24

We have the final answer as

<h3>58 m</h3>

Hope this helps you

5 0

3 years ago

Point A(1,9) and point B(−4,−3) are located within the coordinate plane.

AlekseyPX

Answer:

The answer to your question is 13 units

Step-by-step explanation:

Data

A (1, 9)

B (-4, -3)

distance = ?

Formula

distance = $\sqrt{(x2 - x1)^{2} + (y2 - y1)^{2}}$

Substitution

distance = $\sqrt{(-4 - 1)^{2} + (-3 - 9)^{2}}$

Simplification

distance = $\sqrt{(-5)^{2} + (-12)^{2}}$

distance = $\sqrt{25 + 144}$

distance = $\sqrt{169}$

Result

distance = 13

8 0

3 years ago

Read 2 more answers

Find A, B, and C<br> 7th Grade Math<br> Please help me answer this

xeze [42]

Answer:

A=124 B=60 and C=60

Hope this helps.

3 0

3 years ago