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julia-pushkina [17]
3 years ago
8

Solve for X 4X-(9-3X)=8X-1

Mathematics
1 answer:
Nataliya [291]3 years ago
7 0
4x - (9 - 3x) = 8x - 1

4x - (9) - -(3x) = 8x - 1

4x - 9 + 3x = 8x - 1

7x - 9  = 8x - 1        (-8x from each side)

-x - 9 = -1                (+9 to each)

-x = 8                     (divide -1 from each side)

x = -8
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A water sprinkler covers a circular area with a diameter of 20 feet. If it is set to cover only an arc measuring 120 degrees, wh
Wewaii [24]

<u>Answer:</u>

The sprinkler will cover 104.66 square feet

<u>Explanation:</u>

A water sprinkler covers a circular area with a diameter D=  20 feet

and radius r = 10 feet

Arc measuring degrees = 120 degree

Area of the Arc = \frac{120}{360} \times \pi \times r^2

                         = \frac{1}{3} \times \pi \times 10^2

                         = \frac{1}{3} \times 3.14 \times 10 \times 10

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The sprinkler will cover an arc area covering 104.66 square feet

4 0
3 years ago
When solving the equation 4(3x^2 +2)-9=8x^2+7. Emily wrote 4(3x + 2)=8x^2 + 16 as her first step. Which property justifies Emily
vfiekz [6]
Hello : 
4(3x² +2)-9=8x²+7 = <span>4(3x^2 +2)-9 +9 =8x²+7 +9 
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6 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! <br><br> What is (f/g)(x) ?
Rudiy27

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<u>Step-by-step explanation:</u>

f(x) = 3x² + 10x - 8

g(x) = 3x² - 2x


\dfrac{f(x)}{g(x)}=\dfrac{3x^2+10x-8}{3x^2-2x}=\dfrac{(3x-2)(x+4)}{x(3x-2)}=\dfrac{x+4}{x}

Restriction on x: the denominator cannot be equal to zero. So,

    x(3x - 2) ≠ 0  

→  x ≠ 0     and     3x - 2 ≠ 0

                             3x       ≠ 2

                               x       \neq \dfrac{2}{3}


8 0
3 years ago
The volume of a cylinder is 4x3 cubic units and its height is x units.
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Answer:

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Step-by-step explanation:

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