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julia-pushkina [17]
3 years ago
8

Solve for X 4X-(9-3X)=8X-1

Mathematics
1 answer:
Nataliya [291]3 years ago
7 0
4x - (9 - 3x) = 8x - 1

4x - (9) - -(3x) = 8x - 1

4x - 9 + 3x = 8x - 1

7x - 9  = 8x - 1        (-8x from each side)

-x - 9 = -1                (+9 to each)

-x = 8                     (divide -1 from each side)

x = -8
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<em />

We're given that <em>θ</em> belongs to the third quadrant, for which both sin(<em>θ</em>) and cos(<em>θ</em>) are negative. So if cos(<em>θ</em>) = -4/5, we get

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tan(2<em>θ</em>) = sin(2<em>θ</em>) / cos(2<em>θ</em>)

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tan(2<em>θ</em>) = (2 (-3/5) (-4/5)) / (2 (-4/5)² - 1)

tan(2<em>θ</em>) = 24/7

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