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3 years ago

Which of the following is a monomial?

1 answer:

5 0

In mathematics, the term "monomial" is used to refer to an algebraic expression that contains only one term.
Monomials can either be:
1- numbers (example: 2, 27,...etc)
2- numbers and variables multiplied together (example: 7xy , 33x,.....etc)
3- variables multiplied together (example: xy, abc, ....etc)

Based on the above explanation, we will find that the choice that fits the definition of monomial is:
the first choice: 12c

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I need answers to these MCAS practice questions ASAP!

Semmy [17]

I’ve attached a photo with my work ....
Hope it helps!!

8 0

3 years ago

Find the area of the shaded region

kogti [31]

Answer:

7. 183 in^2

8. 192.42 m^2

9. 239.4 ft^2

Step-by-step explanation:

7. The figure seems most easily seen as a trapezoid with a triangle removed. The trapezoid has bases of 26 and 14, and a height of 15. So, its area is ...

A = (1/2)(b1 +b2)(h) = (1/2)(26+14)(15) = 300 . . . . . . square inches

The triangle has a base of 26 and a height of 9, so an area of ...

A = (1/2)bh = (1/2)(26)(9) = 117 . . . . . . square inches

Then the shaded area is ...

300 in^2 -117 in^2 = 183 in^2

8. The area of the donut can be found different ways. One way is to multiply the width of the shaded area (3.5 m) by the circumference of its centerline.

The centerline diameter is 21 m - 3.5 m = 17.5 m, so the circumference of that circle is ...

C = πd = π(17.5 m) = 17.5π m

Then the area of the shaded part is ...

(3.5 m)(17.5π m) = 61.25π m^2 ≈ 192.42 m^2

9. As in problem 7, this can be treated as a parallelogram less a triangle. Here, we need to do a little work to find the area of the triangle.

The triangle of interest is a right triangle with hypotenuse 23.8 ft and one leg 21 ft. The Pythagorean theorem can be used to find the other leg:

h = √(23.8^2 -21^2) = √125.44 = 11.2

Then the area of the triangle is ...

A = (1/2)bh = (1/2)(21)(11.2) = 117.6 . . . ft^2

The area of the parallelogram (including the triangle) is ...

A = bh = (23.8 ft)(15 ft) = 357 ft^2

So, the shaded area is the difference ...

357 ft^2 -117.6 ft^2 = 239.4 ft^2

_____

<em>Comment on significant digits</em>

The area in problem 8 may be considered to be 192.325 m^2 if you are required to use 3.14 as the value for pi. Since that value is only good to 3 significant digits, it is quite pointless to report the answer to 6 significant digits when using that value. It is quite reasonable to use 192 m^2 for the answer, especially if you're required to round to whole numbers.

8 0

3 years ago

On the first day that tickets to the school play were sold, 100 tickets were sold for $230. Regular tickets cost $3 and student

algol [13]

30 of the $3 tickets were sold
70 of the $2 tickets were sold.

(3*30) + (2*70) = 230

6 0

4 years ago

Read 2 more answers

1 ≤ n, k ≤ 10 ^ 5 1 ≤ x ≤ 10 ^ 5<br> Alguém me ajuda?

enot [183]

Answer:

ask your teacher for help

Step-by-step explanation:

8 0

3 years ago

Customers arrive at a grocery store at an average of 2.1 per minute. Assume that the number of arrivals in a minute follows the

Black_prince [1.1K]

Answer:

a) P(2)=0.270

b) P(X>3)=0.605

c) P=0.410

Step-by-step explanation:

We know that customers arrive at a grocery store at an average of 2.1 per minute. We use the Poisson distribution:

$\boxed{P(k)=\frac{\lambda^k \cdot e^{-\lambda}}{k!}}$

a) In this case: $\lambda=2.1$

$P(2)=\frac{2.1^2 \cdot e^{-2.1}}{2}\\\\P(2)=0.270$

Therefore, the probability is P(2)=0.270.

b) In this case: $\lambda=2\cdot 2.1=4.2$

$P(X>3)=1-P(X\leq 3)\\\\P(X>3)=1-\sum_{x=0}^3 \frac{4.2^x \cdot e^{-4.2}}{x!}\\\\P(X>3)=1-0.395\\\\P(X>3)=0.605$

Therefore, the probability is P(X>3)=0.605.

c) We know that two customers came in in the first minute. That is why we calculate the probability of at least 5 customers entering the other 2 minutes.

In this case: $\lambda=2\cdot 2.1=4.2$

$P(X\geq 5)=1-P(X$

Therefore, the probability is P=0.410.

4 0

3 years ago