The second midpoint is (-15,8)
Answer:
12p x (15 x 25) I might not be correct :')
Answer:
(A) 2 meter
Step-by-step explanation:
It is given that the ladder forms a 72º angle with the ground and rests against the house at a spot that is 6 meters high.
Let the measure of bottom of the ladder from the wall be x, then using the trigonometry, we have





≈
Thus, option A is correct.
Answer:
Minimum 8 at x=0, Maximum value: 24 at x=4
Step-by-step explanation:
Retrieving data from the original question:
![f(x)=x^{2}+8\:over\:[-1,4]](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%2B8%5C%3Aover%5C%3A%5B-1%2C4%5D)
1) Calculating the first derivative

2) Now, let's work to find the critical points
Set this
0, belongs to the interval. Plug it in the original function

3) Making a table x, f(x) then compare
x| f(x)
-1 | f(-1)=9
0 | f(0)=8 Minimum
4 | f(4)=24 Maximum
4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.
4x^2 - 36 = 0
4x^2 = 36
x^2 = 9
x = 3 or -3
the answer is C