Answer: a) Q= 5units
b) R= $75
Step-by-step explanation:
The maximum revenue is at dR/dq = 0
Revenue = price x quantity of demand = p × q
Substituting p = 30- 3q
R = (30-3q) × q
R= 30q- 3q2 (q2 = q raised to the power of 2)
dR/dq = 30- 6q = 0
6q = 30
q= 30/6= 5
q= 5 units
R = pq= 30q- 3q2
R= 30(5) - 3( 5×5)
R= 150- 75
R= $75
Goodluck...
Answer:
39
Step-by-step explanation:
Let x = number of child tickets sold.
Cost of x child tickets is x * 5.30 = 5.3x.
"three times as many adult tickets as child tickets were sold"
Number of adult tickets sold: 3x
Cost of 3x adult tickets is 3x * 8.40 = 25.2x
Cost of all tickets is 5.3x + 25.2x = 30.5x
Cost of all tickets is $1189.50
30.5x = 1189.5
x = 1189.5/30.5
x = 39
Answer: 39
Answer:
-1
Step-by-step explanation:
Range are the output functions f(x) for input functions x
Since the minimum input functions is -2, we are to find the output that gives the lowest value
Given
F(x) = -2x + 5
Whn x = -2
F(-2) = 2(-2)+5
F(-2) = -4+5
F(-2) = 1
When x = 3
F(3) = -2(3)+5
F(3) = -6+5
F(3) = -1
This shows that the minimum value function is -1
