3 years ago

What is the answer, I’m having a hard time understanding it.:(

Mathematics

1 answer:

svet-max [94.6K]3 years ago

5 0

A.1

B.15

I have already answered this on your previous question.

Hope this helps!

You might be interested in

BRAINLIEST ASAP! PLEASE HELP ME :)

Afina-wow [57]

Answer:

$\large \boxed{\textbf{30.54 yr}}$

Step-by-step explanation:

For species A,

$P =2000e^{0.05t}$

For species B,

$P =5000e^{0.02t}$

When their populations are equal,

$\begin{array}{rcl}2000e^{0.05t} & = & 5000e^{0.02t}\\e^{0.05t} & = & 2.5e^{0.02t}\\0.05t & = & \ln2.5 + 0.02t\\0.05t & = & 0.9163 + 0.02t\\0.03t & = & 0.9163\\t& = & \dfrac{0.9163}{0.03}\\\\& = & \mathbf{30.54}\\\end{array}\\\text{The populations of species A and B will be the same in $\large \boxed{\textbf{30.54 yr}}$}$