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san4es73 [151]
1 year ago
8

Can u help me wirh some questions please

Mathematics
1 answer:
Pavel [41]1 year ago
5 0

Find the closest whole number estimate for 3.8 and 6.1

The estimate for both numbers are, 4 and 6.

3.8 is rounded up to the nearest whole number, while 6.1 is rounded down to 6because the 1 after the decimal is an insignificant number (its less than 5)

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The length of a swimming pool is 22 ft. The width is 40 ft. If the volume of the pool is 2,500 ft³, which equation below could b
AURORKA [14]
The equation best used would be 2500=22*40*d
5 0
3 years ago
Read 2 more answers
Frn3n ionfrnffn kfrk jfrnfn
kvasek [131]
I tried to help but couldn’t :)
5 0
3 years ago
mr.rogers bought a computer that cost 2,500. the sales tax rate was 7% how much did he pay for the computer
Anna [14]

Answer:

it's answered...............

3 0
2 years ago
A body moves s metres in a time t seconds so that s = t3 – 3t2 + 8. Find:
Lady bird [3.3K]

Using derivatives, it is found that:

i) v(t) = 3t^2 - 6t

ii) 9 m/s.

iii) a(t) = 6t - 6

iv) 6 m/s².

v) 1 second.

<h3>What is the role of derivatives in the relation between acceleration, velocity and position?</h3>
  • The velocity is the derivative of the position.
  • The acceleration is the derivative of the velocity.

In this problem, the position is:

s(t) = t^3 - 3t^2 + 8

item i:

Velocity is the <u>derivative of the position</u>, hence:

v(t) = 3t^2 - 6t

Item ii:

v(3) = 3(3)^2 - 6(3) = 27 - 18 = 9

The speed is of 9 m/s.

Item iii:

Derivative of the velocity, hence:

a(t) = 6t - 6

Item iv:

a(2) = 6(2) - 6 = 6

The acceleration is of 6 m/s².

Item v:

t for which a(t) = 0, hence:

6t - 6 = 0

6t = 6

t = \frac{6}{6}

t = 1

Hence 1 second.

You can learn more about derivatives at brainly.com/question/14800626

7 0
2 years ago
PLEASE HELP! I HAVE TWO QUESTIONS AND WILL GIVE 100PTS AND BRAINLIEST IF CORRECT!
Volgvan

Answer:

1) $283.50

2) 65.21 meters.

Step-by-step explanation:

Part 1)

We know that a spool of ribbon holds 6.75 meters.

A craft club buys 21 spools.

So, the total length of ribbon bought is:

T=21(6.75)=141.75\text{ meters}

Each meter costs $2. So, the total cost will be:

141.75(2)=\$ 283.50

Part 2)

A spool holds 6.75 meters.

We bought 21 of them, so that total length we have is 141.75 meters.

The club used 76.54 meters.

So, the amount of ribbon that is left is represented by:

141.75-76.54

Subtract:

=65.21\text{ meters}

So, 65.21 meters of ribbon will be left.

7 0
3 years ago
Read 2 more answers
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