Answer:
82.79MPa
Step-by-step explanation:
Minimum yield strength for AISI 1040 cold drawn steel as obtained from literature, Sᵧ = 490 MPa
Given, outer radius, r₀ = 25mm = 0.025m, thickness = 6mm = 0.006m, internal radius, rᵢ = 19mm = 0.019m,
Largest allowable stress = 0.8(-490) = -392 MPa (minus sign because of compressive nature of the stress)
The tangential stress, σₜ = - ((r₀²p₀)/(r₀² - rᵢ²))(1 + (rᵢ²/r²))
But the maximum tangential stress will occur on the internal diameter of the tube, where r = rᵢ
σₜₘₐₓ = -2(r₀²p₀)/(r₀² - rᵢ²)
p₀ = - σₜₘₐₓ(r₀² - rᵢ²)/2(r₀²) = -392(0.025² - 0.019²)/2(0.025²) = 82.79 MPa.
Hope this helps!!
Answer:
Area of segment = 9.8 cm² (Approx.)
Step-by-step explanation:
Given:
Angle θ = 120°
Radius of circle = 4 cm
Find:
Area of segment
Computation:
Area of segment = [θ/360][π][r]² - [1/2][r²][sinθ]
Area of segment = [120/360][3.14][4]² - [1/2][4²][sin120]
Area of segment = [0.333][3.14][16] - [0.5][16][0.866]
Area of segment = 16.7299 - 6.28
Area of segment = 9.8019
Area of segment = 9.8 cm² (Approx.)
Answer:
the answer is the first is 6 2nd is 4 and the last is 24 idek how its college because im in 6 and this is one of my quistions
Step-by-step explanation:
i dont fk
Answer:
7:02
Step-by-step explanation:
Answer:
should be the first one.
Step-by-step explanation:
x+1>5
-1 -1
x>4
