<span>Differentiation of </span><span>Cos(inv) {(a+bcosx)/(b+acosx)} =</span><span> -(((a + b Cos[x])/(Sqrt[1 - x^2] (b + ArcCos[x])^2) - (b Sin[x])/(b + ArcCos[x]))/Sqrt[1 - (a + b Cos[x])^2/(b + ArcCos[x])^2])</span>
Answer:
....................................
Step-by-step explanation:hope i helped
Answer:
x={7,3}
Step-by-step explanation:
x^2-2x+9+12=0
x^2-2x+21=0
(x-7)(x-3)=0
x-7=0
x=7
x-3=0
x=3
so
x={7,4}
8 litres (amount of 20% solution needed) and 7 litres for (amount of 50% solution needed)
<u>Step-by-step explanation:</u>
Let consider ‘x’ for 20% acid solution and (15 – x) for 50% acid solution. And so, the equation would be as below,
20% in x + 50% in (15 – x) = 15 litres of 34%
Convert percentage values, we get
0.20(x) + 0.50 (15 – x) = 15 (0.34)
0.20 x + 7.5 – 0.50 x = 5.1
-0.3 x + 7.5 = 5.1
0.3 x = 7.5 – 5.1
0.3 x = 2.4
Apply ‘x = 8’ value in (15 – x) we get,
15 – 8 = 7 litres
The value of 7 litres for (amount of 50% solution needed)
The definition of absolute value is the magnitude of a number without the sign.
Hope this helps!