B would be the correct anwser
The <span>hardy-weinberg equation is
p2 + 2pq + q2 = 1
where are already given with
c = 0.1 and C = 0.9
SO
p2 = 0.9^2
p2 = 0.81
q2 = 0.01
0.81 + 2pq - 0.01 = 1
2pq = 0.18
The answers are
CC = 0.81
cc = 0.01
Cc = 0.18</span><span />
Answer:
An example of zymogen is pepsinogen. Pepsinogen is the precursor of pepsin. Pepsinogen is inactive until it is released by chief cells into HCl. The latter partially activates pepsinogen. Pepsinogen will be fully converted into pepsin when an inhibiting peptide unit is removed.
Explanation:
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