Answer:
3x^22−x^2+3
Step-by-step explanation:
Let's simplify step-by-step.
3x^22+2x+4−(x2+2x+1)
Distribute the Negative Sign:
=3x^22+2x+4+−1(x2+2x+1)
=3x^22+2x+4+−1x2+−1(2x)+(−1)(1)
=3x&22+2x+4+−x2+−2x+−1
Combine Like Terms:
=3x22+2x+4+−x2+−2x+−1
=(3x22)+(−x2)+(2x+−2x)+(4+−1)
=3x22+−x2+3
Answer:
=3x22−x2+3
Answer:
25x
Step-by-step explanation:
6x + 9 = 25x
Slope = (-2 + 2) / (4 + 7 ) = 0/11 = 0
answer
0
Answer:
The values of 
so that 
have vertical asymptotes are 
, 
, 
, 
, 
.
Step-by-step explanation:
The function cosecant is the reciprocal of the function sine and vertical asymptotes are located at values of so that function cosecant becomes undefined, that is, when function sine is zero, whose periodicity is . Then, the vertical asymptotes associated with function cosecant are located in the values of of the form:
, 
In other words, the values of so that have vertical asymptotes are , , , , .
