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finlep [7]
3 years ago
14

Pre cacl pleaseeeee help. the options are in the attachments as well

Mathematics
1 answer:
ivanzaharov [21]3 years ago
3 0

Answer:

The values of x so that y = \csc x have vertical asymptotes are -2\pi, -\pi, 0, \pi, 2\pi.

Step-by-step explanation:

The function cosecant is the reciprocal of the function sine and vertical asymptotes are located at values of x so that function cosecant becomes undefined, that is, when function sine is zero, whose periodicity is \pi. Then, the  vertical asymptotes associated with function cosecant are located in the values of x of the form:

x = 0\pm \pi\cdot i, \forall \,i\in \mathbb{N}_{O}

In other words, the values of x so that y = \csc x have vertical asymptotes are -2\pi, -\pi, 0, \pi, 2\pi.

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Which is the net for the figure shown?
Nataliya [291]

Answer:

The third one, with the sideways "z" shape.

Step-by-step explanation:

When folded, this net shape will become the new figure.

3 0
3 years ago
State TWO (2) examples of continuous random variable.
Contact [7]

Answer:

example 1 :

a number of patients in doctor surgery

example 2:

a number of children in a family

<h3>Request:</h3>

if it help full please mark as brain list

5 0
3 years ago
What is the probability that all the roots of x2 + bx + c = 0 are real? [0,1]?
notsponge [240]

x^2+bx+c will have real roots when the discriminant of the quadratic, \Delta=b^2-4c, is non-negative, i.e.

b^2-4c\ge0\implies b^2\ge4c

Your question about probability is currently impossible to answer without knowing exactly what the experiment is. Are you picking b,c at random from some interval? Is the choice of either distributed a certain way?

I'll assume the inclusion of "[0,1]" in your question is a suggestion that both b,c are chosen indepently of one another from [0, 1]. Let B,C denote the random variables that take on the values of b,c, respectively. I'll assume B,C are identical and follow the standard uniform distribution, i.e. they each have the same PDF and CDF as below:

f_X(x)=\begin{cases}1&\text{for }0

F_X(x)=\begin{cases}0&\text{for }x

where X is either of B,C.

Then the question is to find P(B^2\ge4C). We have

P(B^2\ge4C)=P\left(C\le\dfrac{B^2}4\right)

and we can condition the random variable C on the event of B=b by supposing

P\left(C\le\dfrac{B^2}4\right)=P\left(\left(C\le\dfrac{B^2}4\right)\land(B=b)\right)=P\left(C\le\dfrac{B^2}4\mid B=b\right)\cdot P(B=b)

then integrate over all possible values of b.

=\displaystyle\int_{-\infty}^\infty P\left(C\le\dfrac{b^2}4\right)f_B(b)\,\mathrm db

=\displaystyle\int_{-\infty}^\infty F_C\left(\dfrac{b^2}4\right)f_B(b)\,\mathrm db

=\displaystyle\int_0^1\dfrac{b^2}4\,\mathrm db=\frac1{12}

4 0
3 years ago
What expression is represented in the model below x y y y y2
Andrei [34K]
X ・y^5
x times y to the fifth
5 0
3 years ago
how many solutions will this system of equations have? y = -3.5x - 3.5 y = -3.5x 3.5 no solution infinite solutions one solution
statuscvo [17]
<span>y = -3.5x - 3.5
y = -3.5x 3.5

I do not see a sign for the constant term (y-intercept) in the second equation.
In any case, since the equation reads y=-3.5x + (y-intercept) in both cases, the lines are parallel to each other.
If the y-intercepts are identical, then the equations are also identical, therefore there are infinitely many solutions.
If the y-intercepts are different (e.g. +3.5 and -3.5), then the two equations form distinct (i.e. not coincident) parallel lines, and therefore has solution.
So it depends on the missing sign, and you will be able to judge when the sign is given.</span>
7 0
3 years ago
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