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finlep [7]
3 years ago
14

Pre cacl pleaseeeee help. the options are in the attachments as well

Mathematics
1 answer:
ivanzaharov [21]3 years ago
3 0

Answer:

The values of x so that y = \csc x have vertical asymptotes are -2\pi, -\pi, 0, \pi, 2\pi.

Step-by-step explanation:

The function cosecant is the reciprocal of the function sine and vertical asymptotes are located at values of x so that function cosecant becomes undefined, that is, when function sine is zero, whose periodicity is \pi. Then, the  vertical asymptotes associated with function cosecant are located in the values of x of the form:

x = 0\pm \pi\cdot i, \forall \,i\in \mathbb{N}_{O}

In other words, the values of x so that y = \csc x have vertical asymptotes are -2\pi, -\pi, 0, \pi, 2\pi.

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Help please!posted picture of question
Evgen [1.6K]
The region is in the first quadrant, and the axis are continuous lines, then x>=0 and y>=0
The region from x=0 to x=1 is below a dashed line that goes through the points:
P1=(0,2)=(x1,y1)→x1=0, y1=2
P2=(1,3)=(x2,y2)→x2=1, y2=3
We can find the equation of this line using the point-slope equation:
y-y1=m(x-x1)
m=(y2-y1)/(x2-x1)
m=(3-2)/(1-0)
m=1/1
m=1
y-2=1(x-0)
y-2=1(x)
y-2=x
y-2+2=x+2
y=x+2
The region is below this line, and the line is dashed, then the region from x=0 to x=1 is:
y<x+2 (Options A or B)

The region from x=2 to x=4 is below the line that goes through the points:
P2=(1,3)=(x2,y2)→x2=1, y2=3
P3=(4,0)=(x3,y3)→x3=4, y3=0
We can find the equation of this line using the point-slope equation:
y-y3=m(x-x3)
m=(y3-y2)/(x3-x2)
m=(0-3)/(4-1)
m=(-3)/3
m=-1
y-0=-1(x-4)
y=-x+4
The region is below this line, and the line is continuos, then the region from x=1 to x=4 is:
y<=-x+2 (Option B)

Answer: The system of inequalities would produce the region indicated on the graph is Option B

8 0
3 years ago
132% of what number is 25 nearest tenth
trapecia [35]

Answer:

100%

Step-by-step explanation:

3 0
3 years ago
Last week, 3/4 of the students in Mr. Zanker's class went on a field trip. 5/8 of the
sleet_krkn [62]

The average fraction of students in the two classes who went on the field trip is 11/16

<h3>What is the average fraction of students in the two classes who went on the field trip?</h3>

The given parameters are:

Class 1 = 3/4

Class 2 = 5/8

The average is calculated as

Average = 1/2 * (Class 1 + Class 2)

So, we have

Average = 1/2 * (3/4 + 5/8)

Evaluate

Average = 11/16

Hence, the average fraction of students in the two classes who went on the field trip is 11/16

Read more about average at:

brainly.com/question/20118982

#SPJ1

7 0
2 years ago
Can somebody plz help answer all these questions CORRECT thanksss!
Natali5045456 [20]

Answer:

37%, 93%, 58%, 21%, 54%, 13%, 34%, 90%, 80%, 52%, 35%

Step-by-step explanation:

37/100 = 37%, 93/100 = 93%, 58/100 = 58%, 21/100 = 21%, 54/100 = 54%, 13/100 = 13%, 17/50 = 34/100 = 34%, 9/10 = 90/100 = 90%, 4/5 = 80/100 = 80%, 13/25 = 52/100 = 52%, 7/20 = 35/100 = 35%

3 0
2 years ago
Which image shows a translation of the green quadrilateral JKLM three units to the right and one unit down?
podryga [215]

Answer:

The second option shows the correct translation of 3 units to the right and 1 unit down.

8 0
3 years ago
Read 2 more answers
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