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Inga [223]
3 years ago
8

What's the answer I need help

Mathematics
1 answer:
Olegator [25]3 years ago
8 0
285 
x 71 equals 20235. hope that helps
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PLZ HELP WILL MARK BRAINLIEST
Fantom [35]

Answer:

  g(x) = (1/6)(x +7)^2 -8

Step-by-step explanation:

The transformation ...

  g(x) = a·f(x -h) +k

represents vertical scaling by a factor of 'a', right shift by h units, and up shift by k units. You want the function g(x) for f(x) = x^2, a = 1/6, h = -7, and k = -8. Those transformations give you ...

  g(x) = (1/6)(x +7)^2 -8

6 0
3 years ago
Which function is represented by the graph?
Arisa [49]

Answer:

D the answer it D I just did this

Step-by-step explanation:

3 0
2 years ago
Given the following formula, with A = 27 and t = 3, solve for r. <br> A=p(1+rt)
Nookie1986 [14]

Answer:

<h2>A.r=\frac{27-p}{3p}</h2>

Step-by-step explanation:

The given formula is

A=p(1+rt)

Where A=27 and t=3

To solve for r, first we need to move p

\frac{A}{p}=1+rt

Then, we move the term 1

\frac{A}{p}-1=rt

Finally, we move the factor t

\frac{\frac{A}{p}-1 }{t} =r

Replacing given values, we have

\frac{\frac{27}{p}-1 }{3} =r\\r=\frac{\frac{27-p}{p} }{3} \\r=\frac{27-p}{3p}

Thereofre, the right answer is A.

7 0
3 years ago
Hey guys what is this type of equation/ question called 1 &lt; x &lt; 30
dimulka [17.4K]

Answer:

2,3,4,5,6,7,8,9,10,...29

Step-by-step explanation:

6 0
3 years ago
Ramona is a saleswoman whose base plus commissions amounted to $52,561 last year. If her base pay was $23,960 and she made $77,3
Ksju [112]

Answer:

37%

Step-by-step explanation:

If Ramona received an overall pay of $52,561 last year, $23,960 of which was base pay, we can first subtract these two numbers to find the amount she made from her sales commission:

$52,561 - $23,960 = $28,601

In order to find her percent commission, we can set up a proportion:

\frac{p}{100}=\frac{28,601}{77,300}, where 'p' is her rate of commission

Cross-multiply and divide:  100(28601) = 77300x or 2,860,100 = 77,300x

Or x = 37%

8 0
3 years ago
Read 2 more answers
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