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Ivenika [448]
3 years ago
5

A light bulb consumes

Mathematics
2 answers:
soldier1979 [14.2K]3 years ago
7 0
To determine how long it takes to consume, simply take 15,300 watt hours and divide it by the initial rate of 3600 watt hours per day.
Luba_88 [7]3 years ago
3 0
The equation you'd use to figure this out is 3600x=15,300. 
"x" represents how many days it'd take. So, just solve for x.

3,600x = 15,300
Divide both sides by 3,600 to get x =4.25

The answer is that it'd take 4.25 days to consume 15,300 watt-hours.
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saveliy_v [14]
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3 years ago
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BlackZzzverrR [31]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Consider the following division of polynomials.
Bond [772]

x^4=x^2\cdot x^2. Multiplying the denominator by x^2 gives

x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

-x^3=-x\cdot x^2. Multiplying the denominator by -x gives

-x(x^2+2x+8)=-x^3-2x^2-8x

and subtracting this from the previous remainder gives a new remainder of

(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8

This last remainder is exactly the same as the denominator, so x^2+2x+8 divides through it exactly and leaves us with 1.

What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}

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and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

3 0
2 years ago
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5 0
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Answer:

Step-by-step explanation:

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