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icang [17]
3 years ago
9

Use the distributive property to rewrite the expression and solve. 9 x 72 = 9 ----- + 9 x 2 = ------

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
3 0
9 x 72 = 9 x ? + 9 x 2

72 = 8 x 9 = 4 x 2 x 9

9 x 72 = 9 x 4 + 9 x 2


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anastassius [24]

Answer:

$32

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12 divided by -4 equals-3 .
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The perimeters of square region S and rectangular region R are equal. If the sides of R are in the ratio 2 : 3, what is the rati
Ksivusya [100]
<h2>Answer:</h2>

The ratio of the area of region R to the area of region S is:

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<h2>Step-by-step explanation:</h2>

The sides of R are in the ratio : 2:3

Let the length of R be: 2x

and the width of R be: 3x

i.e. The perimeter of R is given by:

Perimeter\ of\ R=2(2x+3x)

( Since, the perimeter of a rectangle with length L and breadth or width B is given by:

Perimeter=2(L+B) )

Hence, we get:

Perimeter\ of\ R=2(5x)

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Perimeter\ of\ R=10x

Also, let " s " denote the side of the square region.

We know that the perimeter of a square with side " s " is given by:

\text{Perimeter\ of\ square}=4s

Now, it is given that:

The perimeters of square region S and rectangular region R are equal.

i.e.

4s=10x\\\\i.e.\\\\s=\dfrac{10x}{4}\\\\s=\dfrac{5x}{2}

Now, we know that the area of a square is given by:

\text{Area\ of\ square}=s^2

and

\text{Area\ of\ Rectangle}=L\times B

Hence, we get:

\text{Area\ of\ square}=(\dfrac{5x}{2})^2=\dfrac{25x^2}{4}

and

\text{Area\ of\ Rectangle}=2x\times 3x

i.e.

\text{Area\ of\ Rectangle}=6x^2

Hence,

Ratio of the area of region R to the area of region S is:

=\dfrac{6x^2}{\dfrac{25x^2}{4}}\\\\=\dfrac{6x^2\times 4}{25x^2}\\\\=\dfrac{24}{25}

6 0
3 years ago
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Find the area of the triange below<br><br>units given are cm, cm^2, cm^3​
notsponge [240]

Answer:

A=150\ cm^2

Step-by-step explanation:

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A=\dfrac{1}{2}\times b\times h\\\\A=\dfrac{1}{2}\times 15\times 20\\A=150\ cm^2

So, the area of the triangle is equal to 150\ cm^2.

4 0
3 years ago
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