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zalisa [80]
4 years ago
13

What is the horizontal asymptote of the function f(x)=-2x/x+1

Mathematics
1 answer:
adell [148]4 years ago
5 0
Since the degree of the numerator is the same as the degree of the denominator, then the horizontal asymptote is at

\bf f(x)=\cfrac{\underline{-2} x}{\underline{1} x+1}\implies \stackrel{horizontal~asymptote}{y=\cfrac{-2}{1}\implies y=-2}
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