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emmainna [20.7K]
3 years ago
11

Evaluate the following expression using the values given: Find 3x − y − 3z if x = −2, y = 1, and z = −2. −13 −1 1 13

Mathematics
2 answers:
cluponka [151]3 years ago
6 0

The correct answer is -1

Black_prince [1.1K]3 years ago
3 0
3(-2) - 1 - 3(-2) = -6 - 1 + 6 = -1
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Determine whether the point (1,5) is a solution to the system of equations g(x)=3x+2 f(x)=|x-1|+1
Marizza181 [45]

Point (1,5) is a solution of the equation g(x)=3x+2 and point (1,5) is not a solution of equation f(x)=|x-1|+1

Why point (1,5)<em> </em>is solution of the equation<em> </em>g(x)=3x+2 ?

If point (1,5) is solution of the equation then they must satisfy the equation.

So we need to check one by one

(x,y)=(1,5)

equation g(x)=3x+2

We can write as

y=3x+2\\5=3*1+2\\5=5

So  point (1,5) is solution of this equation.

Equation f(x)=|x-1|+1

We can write as

y=|x-1|+1\\5=|1-1|+1\\5=0+1\\5\neq 1

So point (1,5) is not solution of equation f(x)=|x-1|+1

Learn more about solution of equation here :

brainly.com/question/28048877

#SPJ4

6 0
2 years ago
Solve the formula for T. L=4 πzt+5 πz^3
vekshin1

Answer:

{ \tt{L = 4\pi zt + 5\pi  {z}^{2} }} \\ \\  { \tt{L = \pi z(4t + 5z)}} \\ \\  { \tt{ \frac{L}{\pi z}  = 4t + 5z}} \\  \\ { \tt{4t =  \frac{L}{\pi z}  - 5z}} \\  \\ { \tt{t =  \frac{L}{4\pi z}  -  \frac{5z}{4} }} \\  \\ { \boxed{ \tt{t =  \frac{L - 5\pi {z}^{2} }{4\pi z} }}}

7 0
2 years ago
Which of the following rules describes the function graphed below?
liraira [26]

Answer:

Output = (0.5)(Input) + 1.5

input = 1 , output = (0.5)(1) + 1.5 = 2

input = 3 , output = (0.5)(3) + 1.5 = 3

input = 5 , output = (0.5)(5) + 1.5 = 4

input = -1 , output = (0.5)(-1) + 1.5 = 1

Step-by-step explanation:

8 0
3 years ago
I flew at about 135 mph for about 15 hours how far did I fly
quester [9]
Distance = velocity * time

d=135*15=2025 mi.
4 0
3 years ago
Solve 3x - x + 2 = 12. (1 point)<br> -5<br> 4<br> 7<br> 5
MrRa [10]

Answer: x=5

Step-by-step explanation:

3x - x = 12 - 2

2x = 10

x = 10/2

x = 5

5 0
3 years ago
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