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svetlana [45]
3 years ago
11

How to find the slope of y = 4x -9

Mathematics
2 answers:
dlinn [17]3 years ago
7 0

Answer: 4 is the slope

Step-by-step explanation:

Mark me brainliest if i am correct

BartSMP [9]3 years ago
6 0

Answer:

m=4

Step-by-step explanation:

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Simplify -|-5+2| <br> A. -7 <br> B. -3<br> C. 3<br> D. 7
musickatia [10]

Answer:

the correct anwser is -3 and if you need anymore help the website i use is

Step-by-step explanation:

https://www.tiger-algebra.com

6 0
3 years ago
Read 2 more answers
Solve: The diagonals of a parallelogram are as follows:
pochemuha

Answer:

x = 3, y = 2.

Step-by-step explanation:

I assume that O is the point of intersection of the diagonals. The diagonals of a parallelogram bisect each other so here we have AO = OC and DO = OB.

Therefore 5y + 1 = 6y - 1

1 + 1 = 5y - 5y

2 = y.

2(x + 1) = 3x - 1

2x + 2 = 3x - 1

2 + 1 = 3x - 2x

3 = x.

7 0
3 years ago
Find the correct plugged in formula for each figure.
Mars2501 [29]

Answer:

Area = 40 ( 84)+ 2 *(294)

Step-by-step explanation:

There is only one figure in the attached image and the solution (surface area) is as follows:

The shape can be sub-divided into:

1. Rectangle

Dimension: 40 by 35

2. Rectangle

Dimension: 40 by 28

3. Rectangle

Dimension: 21 by 40

4. 2 triangles

Base: 21 and Height: 28

Calculate area of each and add them up to get the surface area of the figure.

1. Rectangle

Dimension: 40 by 35

A_1 = 40 * 35

2. Rectangle

Dimension: 40 by 28

A_2 = 40 * 28

3. Rectangle

Dimension: 21 by 40

A_3 = 40 * 21

4. 2 triangles

Base: 21 and Height: 28

A_4 = 2 * \frac{1}{2} * 21 * 28

So, the area is:

Area = A_1 +...+A_4

Area = 40 * 35 + 40 * 28 +40 * 21 + 2 * \frac{1}{2} * 21 * 28

Factor out 40

Area = 40 ( 35 +  28 + 21 )+ 2 * \frac{1}{2} * 21 * 28

Area = 40 ( 84)+ 2 * \frac{1}{2} * 21 * 28

Area = 40 ( 84)+ 2 *(294)

8 0
3 years ago
What is 96,989,200 written in scientific notation?
Zina [86]
This one is 9.69892 x 10^2 i believe 
7 0
3 years ago
Read 2 more answers
A triangle OAB is formed where O is the centre of a cricle of radius 12cm, and A and B are endpoints of a 15cm chord. find the a
suter [353]
We are asked to solve for the angle AOB and we are given with the following values:
radius = 12 cm
length of AB = 15 cm

We can solve for angle AOC such as shown below:
sin AOC = opposite/hypotenuse
sin AOC = 7.5/12
∠AOC =38.68°

The angle subtended at the center of the circle is just twice of ∠AOC, then we have:
∠AOB = 38.68° x 2
∠AOB = 77.36°

The answer is 77° 21' 51.75".

3 0
3 years ago
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