Match each equation with the correct property. 5 + 6 = 6 + 5 2(5 + 6) = 2(5) + 2(6) (3 x 5) x 6 = 3 x (5 x 6) 5 x 6 = 6 x 5
2 answers:
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Answer:
<h2>AC = 36.01</h2>Step-by-step explanation:
Given ΔABC and ΔADB, since both triangles are right angled triangles then the following are true.
From ΔADB, AB² = AD²+BD²
Given AB = 24 and AD = 16
BD² = AB² - AD²
BD² = 24²-16²
BD² = 576-256
BD² = 320
BD =
BD = 17.9
from ΔABC, AC² = AB²+BC²
SInce AC = AD+DC and BC² = BD² + DC² (from ΔBDC )we will have;
(AD+DC)² = AB²+ (BD² + DC²)
Given AD = 16, AB = 24 and BD = 17.9, on substituting
(16+DC)² = 24²+17.9²+ DC²
256+32DC+DC² = 24²+17.9²+ DC²
256+32DC = 24²+17.9²
32DC = 24²+17.9² - 256
32DC = 640.41
DC =
DC = 20.01
Remember that AC = AD+DC
AC = 16+20.01
AC = 36.01
Answer:
Step-by-step explanation:
<u>Quadratic Function</u>
Standard Form of Quadratic Function
The standard representation of a quadratic function is:
where a,b, and c are constants.
When the zeros of f (x1 and x2) are given, it can be written as:
f(x)=a(x-x1)(x-x2)
Where a is a constant called the leading coefficient.
We are given the two roots of f: x1=-3 and x2=4, thus:
f(x)=a(x+3)(x-4)
We also know that f(5)=8, thus:
f(5)=a(5+3)(5-4)=8
Operating:
a(8)(1)=8
Solving:
a=1
The function is:
f(x)=1(x+3)(x-4)
Operating: