Question

I need help with this integral question! It is short and easy if you know what you're doing. Due in an hour! Thanks!!!

Answer 1

Answer:

$\int _{-3}^4 R(n)dn =7$

Step-by-step explanation:

Definite Integrals

One of the properties of the definite integrals called This is called internal addition is:

$\int _a^b f(x)dx=\int _a^c f(x)dx+\int _c^b f(x)dx$

We are required to find

$\int _{-3}^4 R(n)dn$

And we are given:

$\int _{-3}^0 R(n)dn =12$

$\int _{0}^4 R(n)dn =-5$

Thus, applying the internal addition property:

$\int _{-3}^4 R(n)dn =\int _{-3}^0 R(n)dn+\int _{0}^4 R(n)dn$

$\int _{-3}^4 R(n)dn =12-5=7$

$\boxed{\int _{-3}^4 R(n)dn =7}$