Question

Find the equation of the circle whose center and radius are given.

Answer 1

Answer: The required equation of circle is $x^2-14x+y^2+6y+9=0$

Step-by-step explanation:

Since we have given that

Centre of circle is (7,-3)

Radius = 7 units

In general , coordinates of centre is (h,k)

and radius is represented by r units.

And the equation of circle is given by

$(x-h)^2+(y-k)^2=r^2\\\\(x-7)^2+(y+3)^2=7^2\\\\x^2-14x+49+y^2+6y+9=49\\\\x^2-14x+y^2+6y+58=49\\\\x^2-14x+y^2+6y=49-58\\\\x^2-14x+y^2+6y=-9$

Hence, the required equation of circle is $x^2-14x+y^2+6y+9=0$

Answer 2

(x-7)^2*(y+3)^2=49 Is the equation of the circle