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Svet_ta [14]
3 years ago
15

in 2010 ,a glacier was 171 meters away from a road.every year since then, it has moved 3 meters closer to the road. at this rate

,in what year will the glacier meet the road?
Mathematics
1 answer:
Svetllana [295]3 years ago
6 0
It will meet the road in 2067
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ZanzabumX [31]

Answer:

a) C(x) = 15000/x + 6x +80

b) Domain of C(x)  { R x>0 }

Step-by-step explanation:

We have:  

Enclosed area = 1500 ft²   = x*y      from which     y  =  1500 / x    (a) where x is perpendicular to the river

Cost = cost of sides of fenced area perpendicular to the river  + cost of side parallel to river + cost of 4 post then

Cost = 10*y + 2*3*x + 4*20 and accoding to (a)  y = 1500/x

Then

C(x)  = 10* ( 1500/x ) + 6*x + 80

C(x) = 15000/x + 6x +80

Domain of C(x)  { R x>0 }

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3 years ago
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kupik [55]

Answer:

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