<h2>
Hello!</h2>
The answer is:
It takes Ella 3 seconds to do a push-up and 3 seconds to do a sit up.
<h2>Why?</h2>
To find how many seconds Ella took to do a push-up and a sit-up we must write two equations using the given information.
Let be "x" the time needed to push-ups and "y" be the time needed to do sit-ups.
So, writing the equations we have:
First equation,
If she can do 13 push-ups and 7 sit-ups in 60 seconds, we have:

Second equation,
If she can do 13 push-ups and 19 sit-ups in 96 seconds, we have:

Now, creating a system of equations, and using the reduction method to solve it, we have:

Multiplying the first equation by -1, we have:


Then, substituting "y" into the first equation, we have:





Hence, we have that It takes Ella 3 seconds to do a push-up and 3 seconds to do a sit up.
Have a nice day!
Answer:
Step-by-step explanation:
f(x) = -8x + 20
f(-1) = -8* -1 + 20 = 8+20 =28
5 - 2[f(-1)] = 5 - 2*28 = 5 - 56 = -51
Answer:
The parametric equations for the tangent line are
:
x = Cos(10) - t×Sin(10)
y = Sin(10) + t×Cos(10)
z = 20 + 2t
Step-by-step explanation:
When Z=20:
Z=2t=20 ⇒ t=10
The point of tangency is:
r(10)= Cos(10) i + Sin(10) j + 20 k
We have to find the derivative of r(t) to get the tangent line:
r'(t)= -Sin(t) i + Cos(t) j + 2 k
The direction vector at t=10 is:
r'(10)= -Sin(10) i + Cos(10) j + 2 k
So, the equation of the tangent line is given by:
x = cos 10 -t×Sin(10)
y = sin 10 + t×Cos(10)
z = 20 + 2t