To solve this problem, we are going to use the formula for
work which is Fd where x and y are measured separately.
X direction: W = 13.5 x 230 = 3105 Joules
Y direction: W = -14.3 x -165 = 2360 Joules
So the total work is getting the sum of the two: 3105 + 2360
= 5465 Joules
The flashlight is powered by one or more batteries.
Batteries supply Direct current (DC) .
Answer:
2.11 seconds
Explanation:
We use the kinematic equation for the velocity in a constantly accelerated motion under the acceleration of gravity (g):
His speed per hour was 5.8km and the total of 6 hours is 35km
Answer:
Explanation:
We know that at pointed corner of a conductor , charge accumulate ie electric field is maximum . Ar pointed corner , radius of curvature will be least . That is why charge leakage is greatest at pointed corner of a charged conductor.
a ) Electric field will be 26.0 kN/C at the point where radius of curvature is greatest .
b ) So electric field will be 66 kN /C at the point where radius of curvature is smallest .
