Answer:
circuito paralelo
Explanation:
Siempre el circuito en paralelo dara una resistencia menor. Recuerda que las resistencias se suman en el circuito en serie, an cambio en el circuito en paralelo, la corriente se bifurca de manera de circular con mayor intensidad por las ramas que tengan menos resistencia, y tal situacion llevara siempre a producir una menor resistencia equivalente.
Answer:
Number of coil in the output is 39938
Explanation:
We have given a step up transformer
Input voltage of transformer, that is primary voltage ![v_p=20000volt](https://tex.z-dn.net/?f=v_p%3D20000volt)
Output voltage, that is secondary voltage ![v_s=355000volt](https://tex.z-dn.net/?f=v_s%3D355000volt)
Number of turns in primary ![N_p=2250](https://tex.z-dn.net/?f=N_p%3D2250)
For transformer we know that ![\frac{V_p}{V_s}=\frac{N_p}{N_s}](https://tex.z-dn.net/?f=%5Cfrac%7BV_p%7D%7BV_s%7D%3D%5Cfrac%7BN_p%7D%7BN_s%7D)
![\frac{20000}{355000}=\frac{2250}{N_s}](https://tex.z-dn.net/?f=%5Cfrac%7B20000%7D%7B355000%7D%3D%5Cfrac%7B2250%7D%7BN_s%7D)
![N_s=39937.5](https://tex.z-dn.net/?f=N_s%3D39937.5)
As the number of turns can not be in fraction so number of turns in the output coil is 39938
Answer:
Zero
Explanation:
The work done by a force on an object is given by:
![W=Fd cos \theta](https://tex.z-dn.net/?f=W%3DFd%20cos%20%5Ctheta)
where
F is the magnitude of the force
d is the displacement of the object
is the angle between the direction of the force and the displacement of the object
In this situation, the force is the force of gravity acting on the satellite. This force always points towards the centre of the trajectory, so it is always perpendicular to the direction of motion of the satellite (since the orbit is circular), so
and
. Therefore, the work done by gravity is also zero.
So the problem are asking to find the value of G base on the formula of the said equation of the magnitude of gravitational attraction on either body. Base on that, the possible answer or the derived formula of the said function is G = Fr^2/m1m2. I hope you are satisfied with my answer and feel free to ask for more