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luda_lava [24]
3 years ago
6

What is the equation in point slope form of the line that passes through the point (−1, −3) and has a slope of 4?

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
7 0

The point-slope form:

y-y_1=m(x-x_1)

We have the slope m = 4 and the point (-1, -3). Substitute:

y-(-3)=4(x-(-1))\\\\\boxed{y+3=4(x+1)}

vivado [14]3 years ago
7 0

Answer:


Step-by-step explanation:

About Point Slope Form:

  • Y- Y1 = m (x -X1)
  • m is the slope
  • Y1 & X1 is a point on the line
  • The form allows you to identify the slope & the point on the line

Y - 3 = 4 (x - -1)


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A test is normally distributed with a mean of 70 and a standard deviation of 10. Todd
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3 years ago
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6 0
3 years ago
Find an upper limit for the zeroes 2x^4 -7x^3 + 4x^2 + 7x - 6 = 0
erik [133]

<u>Answer-</u>

2 is the upper limit for the zeros.

<u>Solution-</u>

The given function f(x) is,

2x^4 -7x^3 + 4x^2 + 7x - 6 = 0

For calculating the zeros,

\Rightarrow f(x)=0

\Rightarrow 2x^4 -7x^3 + 4x^2 + 7x - 6 = 0

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\Rightarrow (x-2)(2x^3-3x^2-2x+3)=0

\Rightarrow (x-2)(x^2(2x-3)-1(2x-3))=0

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