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3 years ago

What is the equation in point slope form of the line that passes through the point (−1, −3) and has a slope of 4?

Mathematics

2 answers:

Dmitry_Shevchenko [17]3 years ago

7 0

The point-slope form:

$y-y_1=m(x-x_1)$

We have the slope m = 4 and the point (-1, -3). Substitute:

$y-(-3)=4(x-(-1))\\\\\boxed{y+3=4(x+1)}$

vivado [14]3 years ago

7 0

Answer:

Step-by-step explanation:

About Point Slope Form:

Y- Y1 = m (x -X1)
m is the slope
Y1 & X1 is a point on the line
The form allows you to identify the slope & the point on the line

Y - 3 = 4 (x - -1)

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3 years ago

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3 years ago

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3 years ago

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densk [106]

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3 years ago

Find an upper limit for the zeroes 2x^4 -7x^3 + 4x^2 + 7x - 6 = 0

erik [133]

<u>Answer-</u>

2 is the upper limit for the zeros.

<u>Solution-</u>

The given function f(x) is,

$2x^4 -7x^3 + 4x^2 + 7x - 6 = 0$

For calculating the zeros,

$\Rightarrow f(x)=0$

$\Rightarrow 2x^4 -7x^3 + 4x^2 + 7x - 6 = 0$

$\Rightarrow 2x^4-4x^3-3x^3+6x^2-2x^2+ 4x+3x-6=0$

$\Rightarrow 2x^3(x-2)-3x^2(x-2)-2x(x-2)+3(x-2)=0$

$\Rightarrow (x-2)(2x^3-3x^2-2x+3)=0$

$\Rightarrow (x-2)(x^2(2x-3)-1(2x-3))=0$

$\Rightarrow (x-2)(x^2-1)(2x-3)=0$

$\Rightarrow (x-2)(x+1)(x-1)(2x-3)=0$

$\Rightarrow x-2=0,\ x+1=0,\ x-1=0,\ 2x-3=0$

$\Rightarrow x=2,\ x=-1,\ x=1,\ x=\frac{3}{2}$

From all the 4 roots, it can be obtained that 2 is the greatest zero.

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3 years ago