Answer:
it's 8
Step-by-step explanation:
the lil hand is on the 8 and the big hand is on the 12
Answer:
3 2/3 is the answer
Step-by-step explanation:
Conversion a mixed number 2 3/
4
to a improper fraction: 2 3/4 = 2 3/
4
= 2 · 4 + 3/
4
= 8 + 3/
4
= 11/
4
To find new numerator:
a) Multiply the whole number 2 by the denominator 4. Whole number 2 equally 2 * 4/
4
= 8/
4
b) Add the answer from previous step 8 to the numerator 3. New numerator is 8 + 3 = 11
c) Write a previous answer (new numerator 11) over the denominator 4.
Two and three quarters is eleven quarters
Divide: 11/
4
: 3/
4
= 11/
4
· 4/
3
= 11 · 4/
4 · 3
= 44/
12
= 4 · 11 /
4 · 3
= 11/
3
Dividing two fractions is the same as multiplying the first fraction by the reciprocal value of the second fraction. The first sub-step is to find the reciprocal (reverse the numerator and denominator, reciprocal of 3/
4
is 4/
3
) of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators. In the next intermediate step , cancel by a common factor of 4 gives 11/
3
.
so you simplify to get 3 2/3
Answer:
A
Step-by-step explanation:
In order to compare all three numbers, you must change them all to have the same form, either all decimal form, all fraction, or all percentages.
The easiest ways to compare are decimal and percentage, as they're practically the same thing. For simplicities sake, though, let's turn all the numbers into decimal.
Since 0.85 is already in decimal form, leave it as it is.
3/4 can be turned into a decimal by putting it into a calculator, but intuitively you should know that it's 0.75. If you don't know a fraction intuitively, you just need to make the fraction into a multiple of denominator 100 and take the numerator. For example:
Numerator is 75.0, now simply move the decimal place up to to get the decimal form 0.75.
91% can be changed into a decimal by moving the decimal place left 2 places. 91.0% turns into 0.91.
Now that you can see the numbers, just rearrange them from least to greatest
0.75<0.85<0.91
equal to A
We are looking for the graph of . which is shown in the attached image.