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Leni [432]
3 years ago
11

jill measured the length of her eraser. She wrote 5 on her paper without the unit. Which metric unit of measure should Jill incl

ude
Mathematics
1 answer:
choli [55]3 years ago
7 0
Its either centimeters or inches.
I prefer centimeters
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Rebecca went on a 240 mile trip to a soccer game. On the way back, due to road construction she had to drive 12 miles per hour s
AlladinOne [14]

Answer:

20mph

Step-by-step explanation:

because you have to divide 240 by 12 and the answer is 20

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3 years ago
One leg of a right triangle is 12, and the hypotenuse is 20.
Eduardwww [97]

Answer:

i believe it is 16.

hope this helped :)

3 0
3 years ago
Subtract. Write your answer in simplest form.<br><br> 3 1/8 - 7/12<br><br> 2<br> 2<br> 3<br> 3
Agata [3.3K]
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i hope this helped
8 0
3 years ago
Historically, a certain region has experienced 92 thunder days annually. (A "thunder day" is day on which at least one instance
DiKsa [7]

Answer:

We conclude that the mean number of thunder days is less than 92.

Step-by-step explanation:

We are given that Historically, a certain region has experienced 92 thunder days annually.

Over the past fifteen years, the mean number of thunder days is 72 with a standard deviation of 38.

<u><em>Let </em></u>\mu<u><em> = mean number of thunder days.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 92 days     {means that the mean number of thunder days is more than or equal to 92}

Alternate Hypothesis, H_A : \mu < 92 days     {means that the mean number of thunder days is less than 92}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                       T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean number of thunder days = 72

             s = sample standard deviation = 38

            n = sample of years = 15

So, <u><em>test statistics</em></u>  =  \frac{72-92}{\frac{38}{\sqrt{15} } }  ~ t_1_4

                               =  -2.038

The value of z test statistics is -2.038.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the t table gives critical value of -1.761 at 14 degree of freedom for left-tailed test.

Since our test statistics is less than the critical value of t as -2.038 < -1.761, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean number of thunder days is less than 92.

7 0
3 years ago
NEED HELP ASAP!!!!!! What is another way to say "to the third power"?
Dovator [93]

Answer:

A number to the third power would be a number cubed, so the answer is "Cubed".

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3 years ago
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