y = -
(x - 5)² + 4
the equation of a quadratic in standard form is
y = a(x - h)² + k ( where (h , k ) are the coordinates of the vertex and a is a multiplier )
given vertex = ( 5, 4 ) then
y = a(x - 5)² + 4 ( to find a substitute (7 , 1 ) into the equation )
1= 4a + 4
4a = - 3 ⇒ a = - 
y = -
(x - 5)² + 4 ← ( in vertex form )
if i'm wrong i'm sorry but i think the answer is C
1 yard = 3 feet
2 yards = 6 feet
2 feet * 3 = 6 feet
so 5.5 ft * 3 = 16.5 feet, so pole is 16 feet 6 inches
The correct given equation is:
v = [3 (h + 1)^2.5 + 580 h – 3] / 10 h
So to solve for the instantaneous velocity at t = 1, we
must set h = 0. However we cannot do that since h is in denominator and a
number divided by a denominator is infinite. Therefore we must set h to
something almost zero. In this case, h = 0.0000001, so that:
at t = 1
v = [3 (0.0000001 + 1)^2.5 + 580 (0.0000001) – 3] / 10 *
0.0000001
<span>v = 58.75 ft/s</span>
Answer:
Pick two points on the line and determine their coordinates. Determine the difference in y-coordinates of these two points (rise). Determine the difference in x-coordinates for these two points (run). Divide the difference in y-coordinates by the difference in x-coordinates (rise/run or slope).
Step-by-step explanation: