Answer:
4 brothers and 3 sisters
Step-by-step explanation:
Let x be the number of brothers and y be the number of sisters in the family.
1. Each brother has x-1 brothers and y sisters. If each brother has as many sisters as brothers, then
2. Each sister has y-1 sisters and x brothers. If each sister has twice as many brothers as she has sisters, then
3. Solve the system of two equations:
Then
Hi ;-)
7/9 + 6/8 + 6/3 = 7/8 + 3/4 + 2 =
= 28/32 + 24/32 + 2 = 52/32 + 2 =
= 1 20/32 + 2 = 3 20/32 = 3 5/8
12:10