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cricket20 [7]
3 years ago
6

In a family, each brother has as many sisters as brothers, but each sister has twice as many brothers as she has sisters. How ma

ny brothers and how many sisters are there in this family?
Mathematics
1 answer:
daser333 [38]3 years ago
4 0

Answer:

4 brothers and 3 sisters

Step-by-step explanation:

Let x be the number of brothers and y be the number of sisters in the family.

1.  Each brother has x-1 brothers and y sisters. If each brother has as many sisters as brothers, then

x-1=y.

2. Each sister has y-1 sisters and x brothers. If each sister has twice as many brothers as she has sisters, then

2(y-1)=x.

3. Solve the system of two equations:

\left\{\begin{array}{l}x-1=y\\ \\2(y-1)=x\end{array}\right.\Rightarrow 2(y-1)-1=y,\\ \\2y-2-1=y,\\ \\2y-y=2+1,\\ \\y=3.

Then

x=y+1=3+1=4.

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Answer:

There is a 27.62% probability that exactly 2 of the U.S. residents have blood type AB.

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For each U.S. resident, there are only two outcomes possible. Either they have blood type AB, or they do not. This means that we can solve this problem using binomial probability distribution concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

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In this problem, we have that:

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