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avanturin [10]
3 years ago
10

In 2011, the winner of the Peachtree Road Race ran the 7-kilometer event in 28 minutes. What is the runner's unit rate? If the r

unner completed ina 14-kilometer race, what would be the expected time?
Mathematics
1 answer:
Alex787 [66]3 years ago
7 0

Answer:

unit rate= 4-kilometers/minute   expected time= 56 minutes

Step-by-step explanation:

14 kilometers x 4 kilo/minute = 56 minutes

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11Alexandr11 [23.1K]

Answer:

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When p = 12, t = 2, and s = 1/6, r = 18. If r varies directly with p and inversely with the product of s and t, what is the cons
Ilia_Sergeevich [38]
R = kp/st
18 = 12k/(1/6 x 2)
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The prism is completely filled with 1750 cubes that have edge length of 1/5 ft. What is the volume of the prism? Enter your answ
IgorC [24]

Answer:

14 ft³

Step-by-step explanation:

First, find the volume of a single cube: V = s³, where s = side length

V = s³; s = 1/5

V = (1/5)³

V = 0.008 ft³

**Note: (1/5)³ is equal to 1/125 as a fraction. I put it down in decimal form because it's easier for me to work with decimals.**

Now, to find the volume of the prism (which is <u><em>completely</em></u> filled with cubes), multiply the volume of one cube by the total number of cubes: 1750.

(1750)(0.008)

14 ft³

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2 years ago
A world record was set for the men’s 100-m dash in the 2008 Olympic Games in Beijing by Usain Bolt of Jamaica. Bolt "coasted" ac
Andrei [34K]

Answer:

a) v = 12.21m/s

a = 4.07 m/s²

b)v = 11.24m/s

a =  3.75 m/s²

Step-by-step explanation:

a) Dividing the moviment into two parts:

I - With acceleration

v = v₀ + at

s = s₀ + v₀t + at²/2

  • v₀ = 0
  • s₀ = 0
  • a = ?
  • v = ?
  • t = 3s
  • s = x

v = v₀ + at

v = 3a ⇒ a = v/3

s = s₀ + v₀t + at²/2

x = v/3.3²/2

x = 3v/2

II - Uniform

s = s₀ + vt

s = 100

s₀ = x

v = v

t = 9.69 - 3 = 6.69s

s = s₀ + vt

100 = x + v*6.69

100 = x + 6.69v

As x = 3v/2

100 = 3v/2 + 6.69v

100 = 1.5v + 6.69v

100 = 8.19v

v = 12.21m/s

a = v/3 = 4.07 m/s²

b) Dividing the moviment into two parts:

I - With acceleration

v = v₀ + at

s = s₀ + v₀t + at²/2

  • v₀ = 0
  • s₀ = 0
  • a = ?
  • v = ?
  • t = 3s
  • s = x

v = v₀ + at

v = 3a ⇒ a = v/3

s = s₀ + v₀t + at²/2

x = v/3.3²/2

x = 3v/2

II - Uniform

s = s₀ + vt

s = 200

s₀ = x

v = v

t = 19.30 - 3 = 16.30s

s = s₀ + vt

200 = x + v*16.3

100 = x + 16.3v

As x = 3v/2

200 = 3v/2 + 16.3v

200 = 1.5v + 16.3v

200 = 17.8v

v = 11.24m/s

a = v/3 = 3.75 m/s²

8 0
2 years ago
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