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Olegator [25]
4 years ago
11

What is x if x/3 + x/2=5

Mathematics
1 answer:
Tamiku [17]4 years ago
6 0

you have to simplify it

then isolate the variable

then you will get x=6

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svetlana [45]
<span>retirement savings hope that helps ;)
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7 0
3 years ago
Read 2 more answers
How do I use intercepts to graph 3y= - 5x - 30
expeople1 [14]

Answer:

y-intercept is (0,-10) and x-intercept is (-6,0).  Connect them by a straight line to graph the given equation.

Step-by-step explanation:

The given equation of line is

3y=-5x-30

For x=0,

3y=-5(0)-30

3y=-30

y=-10

So, y-intercept is at point (0,-10).

For y=0,

3(0)=-5x-30

0=-5x-30

5x=-30

x=-6

So, x-intercept is at point (-6,0).

Now, plot the point (0,-10) and (-6,0) on a coordinate plane and connect them by a straight line to graph the given line as shown below.

7 0
4 years ago
Successful implementation of a new system is based on three independent modules. Module 1 works properly with probability 0.9, M
olga nikolaevna [1]

Answer:

The probability is 0.5086

Step-by-step explanation:

The probability P that at least one of these three modules will fail to work properly is calculated as:

P = 1 - P'

Where P' is the probability that all the modules works properly. So, P' os calculated as:

P' = 0.9 * 0.84 * 0.65

P' = 0.4914

Because 0.9 is the probability that module 1 works properly, 0.84 is the probability that module 2 works properly and 0.65 is the probability that module 3 works properly.

Finally, the probability P that at least one of these three modules will fail to work properly is:

P = 1 - 0.4914

P = 0.5086

8 0
4 years ago
Factor 6x(x + 12) – 15(x + 12)
poizon [28]
The answer is 3(2x-5) (x+12)
6 0
2 years ago
Halla la suma de 3, ocho veces un número, y tres veces el mismo número
Svet_ta [14]

Answer:

3 + 11x

Step-by-step explanation:

Nuestra ecuación será: 3 + 8x + 3x

No sabemos qué es x, así que simplemente sumamos términos semejantes y obtenemos 3 + 11x

Espero que esto haya ayudado, por favor marque lo más inteligente, ¡gracias!

7 0
4 years ago
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