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Dmitriy789 [7]
3 years ago
9

Successful implementation of a new system is based on three independent modules. Module 1 works properly with probability 0.9, M

odule 2 works properly with probability 0.84, and Module 3 works properly with probability 0.65. What is the probability that at least one of these three modules will fail to work properly?
Mathematics
1 answer:
olga nikolaevna [1]3 years ago
8 0

Answer:

The probability is 0.5086

Step-by-step explanation:

The probability P that at least one of these three modules will fail to work properly is calculated as:

P = 1 - P'

Where P' is the probability that all the modules works properly. So, P' os calculated as:

P' = 0.9 * 0.84 * 0.65

P' = 0.4914

Because 0.9 is the probability that module 1 works properly, 0.84 is the probability that module 2 works properly and 0.65 is the probability that module 3 works properly.

Finally, the probability P that at least one of these three modules will fail to work properly is:

P = 1 - 0.4914

P = 0.5086

You might be interested in
An economist uses the price of a gallon of milk as a measure of inflation. She finds that the average price is $3.82 per gallon
salantis [7]

Answer:

(a) The standard error of the mean in this experiment is $0.052.

(b) The probability that the sample mean is between $3.78 and $3.86 is 0.5587.

(c) The probability that the difference between the sample mean and the population mean is less than $0.01 is 0.5754.

(d) The likelihood that the sample mean is greater than $3.92 is 0.9726.

Step-by-step explanation:

According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

n=40\\\mu=\$3.82\\\sigma=\$0.33

As <em>n</em> = 40 > 30, the distribution of sample mean is \bar X\sim N(3.82,\ 0.052^{2}).

(a)

The standard error is the standard deviation of the sampling distribution of sample mean.

Compute the standard deviation of the sampling distribution of sample mean as follows:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

    =\frac{0.33}{\sqrt{40}}\\\\=0.052178\\\\\approx 0.052

Thus, the standard error of the mean in this experiment is $0.052.

(b)

Compute the probability that the sample mean is between $3.78 and $3.86 as follows:

P(3.78

                               =P(-0.77

Thus, the probability that the sample mean is between $3.78 and $3.86 is 0.5587.

(c)

If the difference between the sample mean and the population mean is less than $0.01 then:

\bar X-\mu_{\bar x}

Compute the value of P(\bar X as follows:

P(\bar X

                    =P(Z

Thus, the probability that the difference between the sample mean and the population mean is less than $0.01 is 0.5754.

(d)

Compute the probability that the sample mean is greater than $3.92 as follows:

P(\bar X>3.92)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{3.92-3.82}{0.052})

                    =P(Z

Thus, the likelihood that the sample mean is greater than $3.92 is 0.9726.

3 0
3 years ago
3 = 2 – x 3 = 2 – 2 – x 3 = –x 2003-03-02-00-00_files/i0110000.jpg –3 = x A. The student incorrectly applied the multiplication
rewona [7]
Answer:
B. The student did not properly apply the addition property to isolate x

Explanation:
When given an equation to solve, always remember that when you do an external operation (add/subtract/multiply a term or divide by a term) on one side of the equation, the same operation should be applied on the other side in order to maintain the equality of the equation.

Now, let's take a look on the steps done:
Step 1:
3 = 2 - x
Step 2:
3 = 2 - 2 - x
Step 3:
3 = -x

Now, note n step 2, the student wanted to get rid of the 2 next to the x, therefore, he subtracted 2. However, the student did not subtract the 2 from the other side of the equation. Since we're taking addition (we're adding a -2), therefore, the student incorrectly applied the addition property to isolate the x.

The correct steps would be as follows:
Step 1:
3 = 2 - x
Step 2:
3 - 2 = 2 - 2 - x
Step 3:
1 = - x

Hope this helps :)
5 0
3 years ago
Find the nth term of this sequence : 7 , 12 , 17 , 22 , 27 ???
spayn [35]
32 is the answer and it is adding 5 everytime 


4 0
3 years ago
Read 2 more answers
The route used by a certain motorist in commuting to work contains two intersections with traffic signals. The probability that
tekilochka [14]

Answer:

a) P(X∩Y) = 0.2

b) P_1 = 0.16

c) P = 0.47

Step-by-step explanation:

Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.

So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67

Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:

P(X∩Y) = P(X) + P(Y) - P(X∪Y)

P(X∩Y) = 0.36 + 0.51 - 0.67

P(X∩Y) = 0.2

On the other hand, the probability P_1 that he must stop at the first signal but not at the second one can be calculated as:

P_1 = P(X) - P(X∩Y)

P_1 = 0.36 - 0.2 = 0.16

At the same way, the probability P_2 that he must stop at the second signal but not at the first one can be calculated as:

P_2 = P(Y) - P(X∩Y)

P_2 = 0.51 - 0.2 = 0.31

So, the probability that he must stop at exactly one signal is:

P = P_1+P_2\\P=0.16+0.31\\P=0.47

7 0
3 years ago
Plz help out i am so confused
MatroZZZ [7]

Answer:

Me too not trying to get the points but how are u suppose to solve this anyway

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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