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3 years ago

terry sees this offer. refurbished phone 35%off now only £78. how much was the phone before the discountes price?

Mathematics

1 answer:

borishaifa [10]3 years ago

6 0

Answer:

the price now is 100-35=65% of the initial price p

65p/100=78

65p=78*100

p=7800/65

p=120 ( the phone before the discounted price )

Step-by-step explanation:

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Andrea, Justin, and Virginia went to an office supply store. Andrea bought 6 pencils, 7 markers, and 8 erasers. Her total was $1

olga2289 [7]

Answer:

$x=0.25\,,\,y=1.75\,,\,z=0.25$

Step-by-step explanation:

Let $x,y,z$ denotes number of pencils, markers, erasers respectively.

For Andrea:

$6x+7y+8z=15.75\,\,\,(i)$

For Justin:

$6x+8y+5z=16.75\,\,\,(ii)$

For Virginia:

$5x+5y+7z=11.75\,\,\,(iii)$

On subtracting equations (i) and (ii), we get

$(6x+7y+8z)-(6x+8y+5z)=15.75-16.75\\-y+3z=-1\\y-3z=1\\y=1+3z$

Put $y=1+3z$ in equation (i)

$6x+7(1+3z)+8z=15.75\\6x+29z=8.75\,\,\,(iv)$

Put $y=1+3z$ in equation (iii)

$5x+5(1+3z)+7z=11.75\\5x+22z=6.75\,\,\,(v)$

Multiply equation (iv) by 5 and equation (v) by 6 and then subtract both the equations.

$5(6x+29z)-6(5x+22z)=5(8.75)-6(6.75)\\13z=3.25\\z=\frac{3.25}{13}=0.25$

Put $z=0.25$ in equation $y=1+3z$

$y=1+3(0.25)=1.75$

Put $y=1.75\,,\,z=0.25$ in equation (i)

$6x+7(1.75)+8(0.25)=15.75\\6x+12.25+2=15.75\\6x=1.5\\x=0.25$

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3 years ago

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katrin2010 [14]

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$Answer:\ \boxed{B.\ \dfrac{1-n}{n+4}}$

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3 years ago

Find the area of the shape

aliina [53]

Answer:

72 yd^2

Step-by-step explanation:

Separate the shape into a square and a rectangle. Figure out the measurements of each shape then add the total.