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3 years ago

terry sees this offer. refurbished phone 35%off now only £78. how much was the phone before the discountes price?

Mathematics

1 answer:

borishaifa [10]3 years ago

6 0

Answer:

the price now is 100-35=65% of the initial price p

65p/100=78

65p=78*100

p=7800/65

p=120 ( the phone before the discounted price )

Step-by-step explanation:

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PLEASE HELP!? Not that hard.

kobusy [5.1K]

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// Plug this in for variable y in equation [1]

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[1] 0 = 0 => Infinitely many solutions

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2 years ago

Read 2 more answers

1. Joanna is saving up for a new car. Her parents said that once she has $1000 saved up, they would help her

iris [78.8K]

9514 1404 393

Answer:

60 hours

Step-by-step explanation:

We want Joanna's total savings to be ...

bank account + gift + earnings = 1000

300 +100 +10h = 1000

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h = 60 . . . . . . . .divide by 10

Joanna needs to babysit for 60 hours to earn the money she needs.

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2 years ago

1+-w2+9w and I need help cuz I’m on 76 and I’m sooo close help

Gnesinka [82]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Simplify :- 1 + - w² + 9w.

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\large \sf1 + - w ^ { 2 } + 9 w$

Quadratic polynomial can be factored using the transformation $\sf \: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right)$ , where $\sf x_{1} and x_{2}$ are the solutions of the quadratic equation $\sf \: ax^{2}+bx+c=0$ .

$\large \sf-w^{2}+9w+1=0$

All equations of the form $\sf\:ax^{2}+bx+c=0$ can be solved using the quadratic formula: $\sf\frac{-b±\sqrt{b^{2}-4ac}}{2a}$ . The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$\large \sf \: w=\frac{-9±\sqrt{9^{2}-4\left(-1\right)}}{2\left(-1\right)} \\$

Square 9.

$\large \sf \: w=\frac{-9±\sqrt{81-4\left(-1\right)}}{2\left(-1\right)} \\$

Multiply -4 times -1.

$\large \sf \: w=\frac{-9±\sqrt{81+4}}{2\left(-1\right)} \\$

Add 81 to 4.

$\large \sf \: w=\frac{-9±\sqrt{85}}{2\left(-1\right)} \\$

Multiply 2 times -1.

$\large \sf \: w=\frac{-9±\sqrt{85}}{-2} \\$

Now solve the equation $\sf\:w=\frac{-9±\sqrt{85}}{-2}$ when ± is plus. Add -9 to $\sf\sqrt{85}$ .

$\large \sf \: w=\frac{\sqrt{85}-9}{-2} \\$

Divide -9+ $\sf\sqrt{85}$ by -2.

$\large \boxed{ \sf \: w=\frac{9-\sqrt{85}}{2}} \\$

Now solve the equation $\sf\:w=\frac{-9±\sqrt{85}}{-2}$ when ± is minus. Subtract $\sf\sqrt{85}$ from -9.

$\large \sf \: w=\frac{-\sqrt{85}-9}{-2} \\$

Divide $\sf-9-\sqrt{85}$ by -2.

$\large \boxed{ \sf \: w=\frac{\sqrt{85}+9}{2}} \\$

Factor the original expression using $\sf\:ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right)$ . Substitute $\sf\frac{9-\sqrt{85}}{2}$ for $\sf\:x_{1}$ and $\sf\frac{9+\sqrt{85}}{2}$ for $\sf\:x_{2}$ .

$\large \boxed{ \boxed {\mathfrak{-w^{2}+9w+1=-\left(w-\frac{9-\sqrt{85}}{2}\right)\left(w-\frac{\sqrt{85}+9}{2}\right) }}}$

Well, in the picture you inserted it says that it's 8th grade mathematics. So, I'm not sure if you have learned simplification with the help of biquadratic formula. So, if you want the answer simplified only according to like terms then your answer will be ⇨

$\large \sf \: 1 + - w {}^{2} + 9w \\ =\large \boxed{\bf \: 1 - {w}^{2} + 9w}$

This cannot be further simplified as there are no more like terms (you can use the biquadratic formula if you've learned it.)

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2 years ago

12 divided by 127 show your work

Dafna11 [192]

Answer:

10.58

Step-by-step explanation:

7 0

1 year ago

Resuelve el siguiente ejercicio:

exis [7]

Answer:

Cuanto dinero voy a pagar 24 $

Cuanto recibiré de cambio 76 $

Step-by-step explanation:

Mis compras son:

1 lápiz 3,50 $

2 plumas 7,90 $

1Libreta 12,60 $

Lo que quiere decir que compre:

3,50 + 7,90 + 12,60 = 24 $

Si cancelo mis compras con un billete de 100 $ me tienen que dar vuelto por:

100 $ - 24 $ = 76 $

5 0

2 years ago