Ask question

Ask question

All categories

3 years ago

11

terry sees this offer. refurbished phone 35%off now only £78. how much was the phone before the discountes price?

1 answer:

borishaifa [10]3 years ago

6 0

Answer:

the price now is 100-35=65% of the initial price p

65p/100=78

65p=78*100

p=7800/65

p=120 ( the phone before the discounted price )

Step-by-step explanation:

You might be interested in

What is the estimation of 102.3/4.7

attashe74 [19]

100/5 = 20.

But, I'm not really sure how you want to do this.

7 0

3 years ago

A researcher is interested in estimating the mean weight of a semi tracker truck to determine the potential load capacity. She t

FinnZ [79.3K]

Answer:

(19229.11 ,20770.89)

Step-by-step explanation:

We are given the following information:

Sample size, n = 17

Sample mean = 20,000 pounds

Sample standard deviation = 1,500 pounds

Confidence level = 95%

Significance level = 5% = 0.05

95% Confidence interval:

$\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 16 and}~\alpha_{0.05} = \pm 2.119$

$20000 \pm 2.119(\displaystyle\frac{1500}{\sqrt{17}} ) = 20000 \pm 770.89 = (19229.11 ,20770.89)$

4 0

3 years ago

The given lengths are two sides of a right triangle. All three side lengths of the triangle are integers, and together they form

mel-nik [20]

The correct answer is “A” 40,leg

8 0

3 years ago

Enter a numerical expression for the word expression 10 decreased by 4

bulgar [2K]

10-4=6. can it be like this.

7 0

3 years ago

Read 2 more answers

Which expression represents the number 2i4−5i3+3i2+−81‾‾‾‾√ rewritten in a+bi form?

vichka [17]

Answer:

The expression $-1+14i$ represents the number $2i^4-5i^3+3i^2+\sqrt{-81}$ rewritten in a+bi form.

Step-by-step explanation:

The value of $i$ is $i=\sqrt{-1}[tex] or [tex]i^{2}=-1[\tex].Now [tex]i^{4}$ in term of $i^{2}[\tex] can be written as, [tex]i^{4}=i^{2}\times i^{2}$

Substituting the value,

$i^{4}=\left(-1\right)\times \left(-1\right)$

Product of two negative numbers is always positive.

$\therefore i^{4}=1$

Now $i^{3}$ in term of $i^{2}[\tex] can be written as, [tex]i^{3}=i^{2}\times i$

Substituting the value,

$i^{3}=\left(-1\right)\times i$

Product of one negative and one positive numbers is always negative.

$\therefore i^{3}=-i$

Now $\sqrt{-81}$ can be written as follows,

$\sqrt{-81}=\sqrt{\left(81\right)\times\left(-1\right)}$

Applying radical multiplication rule,

$\sqrt{ab}={\sqrt{a}}\sqrt{b}$

$\sqrt{\left(81\right)\times\left(-1\right)}={\sqrt{81}}\sqrt{-1}$

Now, $\sqrt{\left(81\right)=9$ and $\sqrt{-1}}=i$

$\therefore \sqrt{\left(81\right)\times\left(-1\right)}=9i$

Now substituting the above values in given expression,

$2i^4-5i^3+3i^2+\sqrt{-81}=2\left(1\right)-5\left(-i\right)+3\left(-1\right)+9i$

Simplifying,

$2+5i-3+9i$

Collecting similar terms,

$2-3+5i+9i$

Combining similar terms,

$-1+14i$

The above expression is in the form of a+bi which is the required expression.

Hence, option number 4 is correct.

5 0

3 years ago