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kramer
3 years ago
5

Look at the graph shown below:

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
3 0

Answer:

A

Step-by-step explanation:

y=3/4x+4 best represents the line shown below. Because the slope of this graph is 3/4, and the y-intercept is positive 4. Remember that slope=rise/run. You can find the slope very easily by counting, 3 upwards and 4 rightwards.

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6x^2+x-12 in factored form
pychu [463]
6x²+x-12

the first thing we need to do is find 2 numbers that add up to equal the middle term (1) but multiply together to get a product of -72 (-12*6)

two numbers that would fit this is 9 and -8
so now we placed 9x and -8x in place of the middle term

6x²+9x-8x-12

now we look for whats common between the first two numbers and divide them out

6x²+9x = 3x(2x+3)

now we do the same with the last two numbers

-8x-12 = -4(2x+3)

notice how the numbers in brackets are the same (2x+3)
we will keep (2x+3) and then combine the numbers on the outside

once we do that you should get an answer of 

(3x-4)(2x+3)

hope this helped!


5 0
3 years ago
Given a | | b, m∠ 1 = 56° , and m∠2 = 42° , find the measure of the other angles.
stellarik [79]

Did you ever get the answer?

8 0
3 years ago
I need help asap pleaseeee
Naya [18.7K]

Answer:

94

Step-by-step explanation:

im pretty sure this is right

7 0
3 years ago
Read 2 more answers
Help me please the picture below has the question and the answers
andrezito [222]

Answer:

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6 0
3 years ago
ricardo purchased a bunk bed for his children fora sale price of $276.25. The sale price was 65% of the original price. Calculat
nikklg [1K]

Use the formula S=P-PD

S is sale price, original price is P, and PD is discounted percent,

276.25=P-P(.65), I turned the percent into a decimal.

276.25=P(1-.65)

276.25=P(1-.65)

276.25=P(.35)

Now cross multiply.

\frac{276.26}{.35}=\frac{P(.35)}{.35}\\\\P=\frac{276.26}{.35}=789.31

Hope this helps, now you know the answer and how to do it. Stay healthy and safe and HAVE A BLESSED AND WONDERFUL DAY! :-)  

- Cutiepatutie ☺❀❤

6 0
3 years ago
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