Answer:
FOR H_2
![1 \mu mol/L = 2\times 10^{-6} mol/L](https://tex.z-dn.net/?f=1%20%5Cmu%20mol%2FL%20%3D%202%5Ctimes%2010%5E%7B-6%7D%20mol%2FL)
Step-by-step explanation:
Given data:
concentration ![0.6 \mu mol/L](https://tex.z-dn.net/?f=0.6%20%5Cmu%20mol%2FL)
WE KNOW THAT
![ONE\ \mu = 10^{-6}](https://tex.z-dn.net/?f=ONE%5C%20%20%5Cmu%20%3D%2010%5E%7B-6%7D)
therefore
![1 \mu mol/L = 10^{-6} mol/L](https://tex.z-dn.net/?f=1%20%5Cmu%20mol%2FL%20%3D%2010%5E%7B-6%7D%20mol%2FL)
Now for conversion of mol to gram need the molar mass of element in which particular value convert to.
let us take ![H_2](https://tex.z-dn.net/?f=H_2)
we know that molar mass of
is 2 gram
therefore
![1 \mu mol/L = 2\times 10^{-6} mol/L](https://tex.z-dn.net/?f=1%20%5Cmu%20mol%2FL%20%3D%202%5Ctimes%2010%5E%7B-6%7D%20mol%2FL)
let take other example, for ![O_2](https://tex.z-dn.net/?f=O_2)
we know that molar mass of O_2 is 32 gram
therefore
![1 \mu mol/L = 32\times 10^{-6} mol/L](https://tex.z-dn.net/?f=1%20%5Cmu%20mol%2FL%20%3D%2032%5Ctimes%2010%5E%7B-6%7D%20mol%2FL)
Answer:
3x - y =13
Step-by-step explanation:
- y - y1 = m(x - x1)
- y - 2 = m(x - 5)
- distribute
- y - 2 = 3x - 15
- jump -2 across the equal sign and change the sign
- y = 3x - 15 + 2
- combine like terms
- y = 3x - 13
- use this equation to find the standard form
- y = 3x - 13
- jump the x and change the sign
- -3x + y = -13
- x must be positive, so change the sign of everything
- 3x - y = 13
Step-by-step explanation:
1. The first step has 1 block. The second step has 2 blocks. The third step has 3 blocks. So the nth step needs n blocks.
2. A staircase with n steps has 1 + 2 + 3 + ... + n steps. This is an arithmetic sequence where the first term is 1 and the last term is n. The sum of the first n terms is:
y = n/2 (1 + n)
3. Solve for n.
2y = n (1 + n)
2y = n² + n
0 = n² + n − 2y
Using quadratic formula:
n = [ -1 ± √(1 − 4(1)(-2y)) ] / 2
n = [ -1 + √(1 + 8y) ] / 2
Answer:
$77
Step-by-step explanation:
7 people, each person paid 17, 17x7 = 119, salad was 42, 119 - 42 = 77