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Darya [45]
3 years ago
5

Solve and show all steps PLSSS ASAP I NEED HELP TYSM!!!!

Mathematics
2 answers:
gladu [14]3 years ago
6 0

Answer:

n < 6

Step-by-step explanation:

I multiplied the entire equation by 3 to remove the fraction. This got me:

12 + n < 18

I then subtracted 12 (inverse operations) to get:

n < 6

I hope this helps!

abruzzese [7]3 years ago
6 0

Answer:

n=1

Step-by-step explanation:   n/3=3+4 is less than 6

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Which equation has infinite solutions?
Sonja [21]

Answer:

a 3x-7=12x

Step-by-step explanation:

=6.33333333

5 0
3 years ago
A rectangular field is 75 yards wide and 105 yards long
nika2105 [10]

Answer:

width = 72 yards

length = 108 yards

Step-by-step explanation:

Given:

  • Width = 75 yards
  • Length = 105 yards

<u>Area of the field</u> with the given values:

\begin{aligned}\textsf{Area of a rectangle}&=\sf width \times length\\& = \sf 75 \times 105\\& = \sf 7875\:\: yd^2\end{aligned}

To maintain the <u>same perimeter</u>, but <u>change the area</u>, either:

  • decrease the width and increase the length by the same amount, or
  • increase the width and decrease the length by the same amount.

In geometry, length pertains to the <u>longest side</u> of the rectangle while width is the <u>shorter side</u>.  Therefore, we should choose:

  • decrease the <u>width</u> and increase the <u>length</u> by the <u>same amount</u>.

<u>Define the variables</u>:

  • Let x = the amount by which to decrease/increase the width and length.

Therefore:

\implies \sf width \times length < 7875\:\:yd^2

\implies (75-x)(105+x) < 7875

Solve the inequality:

\begin{aligned}(75-x)(105+x) & < 7875\\7875-30x-x^2 & < 7875\\-x^2-30x & < 0\\-x(x+30) & < 0\\x(x+30) & > 0\\\implies x & > 0 \:\: \textsf{ or }\:\:x < - 30\end{aligned}

Therefore, as distance is positive only and the maximum width is 75 yd (since we are subtracting from the original width):

\begin{cases}\textsf{width} = 75 - x\\\textsf{length} = 105 + x\end{cases}

\textsf{where } 0 < x < 75

Therefore, to find the width and length of another rectangular field that has the same perimeter but a smaller area than the first field, simply substitute a value of x from the restricted interval into the found expressions for width and length:

<u>Example 1</u>:

  • Let x = 3

⇒ Width = 75 - 3 = 72 yd

⇒ Length = 105 + 3 = 108 yd

⇒ Perimeter = 2(72 + 108) = 360 yd

⇒ Area = 72 × 108 = 7776 yd²

<u>Example 2</u>:

  • Let x = 74

⇒ Width = 75 - 74 = 1 yd

⇒ Length = 105 + 74 = 179 yd

⇒ Perimeter = 2(1 + 179) = 360 yd

⇒ Area = 1 × 179 = 179 yd²

4 0
1 year ago
Read 2 more answers
10 times as much as _____ is 1/10 of 60000
Elina [12.6K]

0.1 × 60,000 = 10x. Combine the terms on the left side of the equation.

6,000 = 10x. Divide each side by 10.

600 = x

6 0
3 years ago
Read 2 more answers
Suppose we lined up all the people in the world (about 7.4 billion people). Assume that each person occupied 13 inches of the li
finlep [7]

Answer:

The answer to your question is: # of times = 60.7

Step-by-step explanation:

data

7.4 billion people

each person occupied 13 inches

Earth circumference = 25000 miles

length of the lines = 13 in x 7.4 billion people

                               = 13 x 7 400 000 000

                              = 9.62 x 10 ¹⁰ in

Convert in to miles

                     1 mile  --------------- 63360 in

                     x mi     ---------------  9.62 x 10 ¹⁰  in

     x = 1518308.1 mi

Now divide, the line of people by the circumference

         # of times =  1518308.1 mi /  25000 mi = 60.7                          

3 0
3 years ago
The rain caused the river to rise a total of 6 2/3 inches. The river was rising at an average of 2/3 of an dinch each hour. How
icang [17]
6 2/3 divided by 2/3 is 20/3 * 3/2 = 60/6 = 10 hours

I used the trick that dividing two fractions is the same as multiplying by the inverse. (ie., divide by 2/3 is like multiplying with 3/2)
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