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SVETLANKA909090 [29]
4 years ago
14

Geometry Question. Please help

Mathematics
1 answer:
mamaluj [8]4 years ago
3 0
I think your answer might be C i am not sure but i am thinking it is
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Two cubes have surface areas of 72 square feet and 98 square feet. what is the ratio of the volume of the small cube to the volu
Serjik [45]
Let's denote the sides of the small and bigger cubes a and b respectively. Then, we can write that 6a^{2}=72, a=2\sqrt{3} and 6b^{2}=98, b=[tex] \frac{7}{sqrt{3}}. The volume of the smaller cube is 2 sqrt{3} ^{3} =  24 sqrt{3}. The volume of the bigger cube is \frac{7}{sqrt{3}}^{3} = \frac{343}{3sqrt{3}}{. We have to find  \frac{24 sqrt{3}}{frac{343}{3sqrt{3}} = 216/343 
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3 years ago
Diamond used a number line to add. She started counting at 10, and then she counted until she was on the number −4 on the number
Sever21 [200]

Answer:

10 + (-14) = -4

Step-by-step explanation:

Given that,

Diamond used a number line to add. She started counting at 10, and then she counted until she was on the number −4 on the number line.

For addition, she will add 10 and (-14) as follows :

10 + (-14) = -4

So, the crrect option is (b) "10 + (-14) = -4".

8 0
3 years ago
A rectangle has a height of k^2+3k 2 +3k, squared, plus, 3 and a width of k^2+7k 2 +7k, squared, plus, 7. Express the area of th
vlada-n [284]

Answer: k^4+10k^3+21k^2

Step-by-step explanation:

Given

Height of rectangle is h=k^2+3k

Width is w=k^2+7k

The area of the rectangle is given by the multiplication of the height and width

\Rightarrow A=\left(k^2+3k\right)\left(k^2+7k\right)\\\\\Rightarrow A=k^2k^2+k^2\cdot \:7k+3kk^2+3k\cdot \:7k\\\\\Rightarrow A=k^4+10k^3+21k^2

Thus, the area of the rectangle is k^4+10k^3+21k^2.

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3 years ago
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Mrac [35]
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4 years ago
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