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3 years ago

For which equation would x = 3 be a solution?

Mathematics

1 answer:

frutty [35]3 years ago

7 0

1. b , 2. A

this has toooo have 20 or more letters soooo i’m doing thissssss hiiiii

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Multiply the binomial and the trinomial. <br> (x-2)(x^2+2x+4)

malfutka [58]

Answer:

Step-by-step explanation:

To solve this problem, we need to multiple $x$ and -2 by $x^{2} + 2x + 4$ and add the results together:

$x(x^{2} + 2x + 4)$

$x^{3} + 2x^{2} + 4x$

$-2(x^{2} + 2x + 4)$

$-2x^{2} - 4x - 8$

Adding the two together give the following:

$(x^{3} + 2x^{2} + 4x) + (-2x^{2} - 4x - 8)$

$x^{3} - 8$

7 0

4 years ago

235+123= solve using a number line

Agata [3.3K]

The answer is 358....

5 0

4 years ago

If (50)x = 1, what are the possible values of x? Explain your answer

Lelechka [254]

Than you multiplie tha 50 by 1/50 so will get 50/50 what is equal 1

hope this is understandably sure right easy

5 0

3 years ago

The cost of K-12 education per student was $2200 in 1978 and increased to $10,300 in 2008. (Source: Department of Education). (a

kobusy [5.1K]

Answer: $C=270x+2200$

Step-by-step explanation:

Given

Cost per student in the year 1978 is $2200

The cost increases to $10,300 in 2008

Suppose $C=mx+a$ is the linear equation defining the cost per student after x years

Substitute the value for 1978

$\Rightarrow 2200=m(0)+c\\\Rightarrow c=2200$

After 30 years it becomes

$\Rightarrow 10,300=m(30)+2200\\\Rightarrow 30m=8100\\\Rightarrow m=270$

Thus, the linear equation becomes

$\Rightarrow C=270x+2200$

6 0

3 years ago

Prove that can you please prove and explain it plz

Alexandra [31]

Answer:

Step-by-step explanation:

LHS = Sin² ∅ + Sin² ∅*tan² ∅

= Sin² ∅ [1 + tan² ∅ ] {Sec² ∅ - tan² ∅ = 1}

= Sin² ∅ *Sec² ∅

= Sin² ∅ * $\frac{1}{Cos^{2} }$

= Sin² ∅ /Cos² ∅

= tan² ∅ = RHS

8 0

3 years ago

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