Answer:
#include <iostream>
using namespace std;
int main()
{
int i = 45;
for ( i = 45; i <=165; i = i + 6)
cout << i << endl;
}
Explanation:
I corrected your code and highlighted the mistakes. Even though you wrote the correct algorithm, your code did not compile because of the typos you made.
Remember, C++ is a case-sensitive language. That means, "For" is not same as "for".
Generally, variables and keywords are written in lower case. Of course, there are exceptions, such as constant variables are all written in uppercase letter and class names start with an uppercase letter.
Is that a joke... if ain't cheatin you repeatin
Answer:
B
Explanation:
This question demonstrates the concept of method overloading
Method overloading means having different versions of the same method. In this case the method mystery() has three versions. The compiler is able to determine which method to call by their different parameters
The first implementation of mystery requires an array of integers as parameter
The second implementation requires an int variable
The third implementation requires a String
The Method call mystery(6 * 8) will output B because 6*8 evaluates to an integer which is the expected argument.
Answer:
pues de decoracion las llantas de columpios y los cuernos de antenas de tele okey no me presiones estoy en clase y acabo de hacer 11 ejercicios y acaba de empezar ok
