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4 years ago

Re-write this question to make it a statistical question:

2 answers:

7 0

A statistical question is a question asked with the goal of collecting data. You could rewrite the question so that it says something like, “How old were you when..” That way the responses will vary and you would be able to graph and compare them.

coldgirl [10]4 years ago

3 0

Answer:

how old were u or

what was ur age when....

Step-by-step explanation:

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Work out an expression for the nth term of the sequence:<br> 0 1 4 9 16

Harlamova29_29 [7]

Answer:

w²

(w is for whole numbers and starts from 0)

please mark brainliest ♡♡

6 0

3 years ago

4y^2 + 2 =38 <br> Help with work would be greatly appreciated

DIA [1.3K]

4y^2 + 2 - 2 = 38 - 2 (subtract both side by 2)

4y^2 = 36

Divide by 4:

y^2 = 9

y = $\sqrt{9}$

y = 3

5 0

3 years ago

Read 2 more answers

In a set of three lines, a pair of parallel lines is intersected by a transversal. The intersection forms eight special angles.

My name is Ann [436]

Answer:

Part A: 4x = -5(x-18)

Part B: A and B both = 40 degrees

Step-by-step explanation:

Ok, corresponding angles are in the same position on the two parallel lines cut by the transversal. And they are equal in measure. So, upper right = upper right.

So A = B

4x = -5(x -18)

4x = -5x + 90

9x = 90

x = 10

Angle A = 4x = 40 degrees, which means angle B is also 40, but let's show the work:

Angle B = -5(x - 18) = -50 + 90 = 40

7 0

3 years ago

Please help parts b and c

zimovet [89]

Answer:

a = 2

b = 4

c = 8

Step-by-step explanation:

Remember the relationship:

$(a^{x})^{y} = a^{x*y}$

First, in "a" we have:

a) $8^{1/3} = \sqrt[3]{8} = 2$

then in the next ones, we can use the result that we obtained in the part a:

b) $8^{2/3} = (8^{1/3})^2 = (2)^2 = 4$

Now we can do exactly the same in c:

c) where first we need to know that:

2*2*2*2 = 4*4 = 16

then:

2^4 = 16

then:

$\sqrt[4]{16} = 16^{1/4} = 2$

Now let's solve the problem:

$16^{3/4} = (16^{1/4})^3 = (2)^3 = 2*2*2 = 8$

5 0

3 years ago

The length of one leg of a right triangle is 24 feet and the length of the hypotenuse is 40 ft what is the length of the other l

Rama09 [41]

To solve for the other leg, you need to use Pythagorean theory.

The theory states that C^2 = A^2 + B^2

In your case, you have to solve for B.
C = 40 (hypotenuse) A = 24 (leg 1)

The formula rewritten for B is $b= \sqrt{c^{2}-a^{2} }$

Now, you can solve.

$b= \sqrt{c^{2}-a^{2} }

b= \sqrt{40^{2}-24^2 }

b = \sqrt{1600 - 576}

b = \sqrt{1024}

b = 32$

Therefore, B = 32.

So the second leg is 32 feet.

7 0

4 years ago