A = 8i + 6j
b = 4i + 5j
ab = (8i + 6j)(4i + 5j)
ab = 8i(4i + 5j) + 6j(4i + 5j)
ab = 8i(4i) + 8i(5j) + 6j(4i) + 6j(5j)
ab = 32i² + 40ij + 24ij + 30j²
ab = 32i² + 64ij + 30j²
ab = <32, 30>
The answer is D.
Just divide -30 m/s (the change in velocity) by 12 seconds (the time required for the car to come to a stop):
-30 m/s
----------- = - 2,5 m / (sec)^2 (answer)
12 sec
Answer: 158.53 cm
Step-by-step explanation:
We know that the ends of a fishing line spool are circular in shape.
Given : The area of an end of fishing line spool =
(1)
Area of a circle =
(2)
Circumference of a circle =
(3)
, where r is radius of the circle.
From (1) and (2), we have
Circumference of fishing spool =
(using (3))

i.e. Fishing spool required to wind around the spool one time 
⇒ Fishing spool required to wind around the spool 10 times 
Hence, you need 158.53 cm or about 159 cm of fishing line to wind around the spool 10 times.
Answer:
(X-9)(x-3)
Step-by-step explanation: