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shusha [124]
3 years ago
11

Someone help pls:( !!!!!!!!!!

Mathematics
1 answer:
lesantik [10]3 years ago
8 0

Answer:

Multiply both sides by -2 and reverse the inequality symbol

Step-by-step explanation:

since it is division you want to make it multiplication so that you can get the answer easier

-1/2w<12

it cancels out the -1/2 than just multiply 12 and -2 you get -24

w > -24

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Determine whether each function is even, odd, or neither.
Ede4ka [16]

Answer:

a)  f(x) = x² -9

function is an even function

b)  g(x) = |x -3|

function is an even function

c) f(x)= x / x²-1

function is  odd function

d) g(x) = x + x²

Given function is not an even not odd function

This function is neither even or odd

Step-by-step explanation:

<u><em>Explanation</em></u>:-

a) Given f(x) = x² -9

<u><em>Even function </em></u>

If f(-x) = f(x) , then the function is even function.

f(-x) = (-x)² -9

      =  x² -9

      = f(x)

f(-x) = f(x)

∴ Given function is an even function

b)

Given g(x) = |x -3|

<u><em>Even function </em></u>

If g(-x) = g(x) , then the function is even function.

g(-x) = |-(x-3)|

      = |x-3|

g(-x) = g(x)

∴ Given function is an even function

c)

<u><em>odd function</em></u>

If f(-x) =- f(x) , then the function is odd function.

f(-x) = f(-x) = \frac{-x}{(-x)^{2}+1 } = \frac{-x}{x^{2}+1 } = - f(x)

      = -f(x)

f(-x) = -f(x)

∴ Given function is odd function

d)

If g(-x) = g(x) , then the function is even function.

g(x) = x + x²

g(-x) =  -x + (-x)²

     = - (x - x²)

This is not either even or odd function

∴ Given function is neither function

8 0
3 years ago
The equation of a circle is (x + 3)2 + (y + 7)2 = 25. Where is (3, 4) located in relation to the circle?
kupik [55]

Answer:

Midpoint of the circle is (-3, -7)

Distance from (3, 4) to (-3, -7) is > 5 because the x and y difference are alone greater 5.

So, "In the exterior of the circle" is correct.

3 0
3 years ago
Calculate the surface area of the composite figure
zhannawk [14.2K]

Answer:

Below in bold.

Step-by-step explanation:

Total surface area = 1/2 * area of a sphere + area of the side o a cone

=  1/2 * 4 π r^2 + π r L

= 1/2 * 4 π 7^2 + π*7*25

=  307.876 + 549.779

= 857.65 in^2 to nearest hundredth.

8 0
3 years ago
Develop a MATLAB script to generate a 5 panel vertical plot to illustrate how a function changes as the parameters change. On ea
Marat540 [252]

The question is incomplete. Complete question along with Matlab code, explanation, and output results are given below.

Complete Question:

Develop a MATLAB script to generate a 5 panel vertical plot to illustrate how a function changes as the parameters change. On each plot, display the simple sine wave, y(t) = sin(2πt), as a red line. Then, add the following functions to each of the 5-panels as black lines:

y(t) = sin(2πt)  sine function

y1(t)=1+sin(2πt) effect of mean

y2(t)=2sin(2πt) effect of amplitude

y3(t)=sin(4πt) effect of frequency

y4(t)=sin(2πt) - π/4) effect of phase shift

y5(t)=cos(2πt) - π/2) relationship between sine and cosine

Step-by-step explanation:

We are required to show different sinusoidal plots to illustrate the effects of changing mean, amplitude, frequency, phase shift, and relationship of sine and cosine wave.

t=[0:0.01:2*pi] % time vector from 0 to 2pi

y=sin(2*pi*t); % the original sine function  

% effect of mean

y1=1+sin(2*pi*t);  

subplot(5,1,1) % 5 rows, 1 column and last for position

plot(t,y,'k',t,y1,'r')  % this function plots y and y1 with respect to time vector t

% 'k' for black color and 'r' for red color

grid on  

xlabel('time (t)') % x-axis is for time

ylabel('y1(t)')  % y-axis is for function value y(t)

title('effect of mean') % title of the plot

ylim([-3 3]) % limit of y-axis

xlim([0 6]) % limit of x-axis

% effect of amplitude

y2=2*sin(2*pi*t);

subplot(5,1,2)  

plot(t,y,'k',t,y2,'r')  

grid on  

xlabel('time (t)')  

ylabel('y2(t)')  

title('effect of amplitude')  

ylim([-3 3])  

xlim([0 6])  

% effect of frequency

y3=sin(4*pi*t);  

subplot(5,1,3)  

plot(t,y,'k',t,y3,'r')  

grid on  

xlabel('time (t)')  

ylabel('y3(t)')  

title('effect of frequency')  

ylim([-3 3])  

xlim([0 6])  

% effect of phase shift

y4=sin((2*pi*t)-pi/4);  

subplot(5,1,4)  

plot(t,y,'k',t,y4,'r')

grid on  

xlabel('time (t)')  

ylabel('y4(t)')  

title('effect of phase shift')  

ylim([-3 3])  

xlim([0 6])  

% relationship between sine & cosine

y5=cos((2*pi*t)-pi/2);  

subplot(5,1,5)  

plot(t,y,'k',t,y5,'r')  

grid on  

xlabel('time (t)')  

ylabel('y5(t)')  

title('relationship between sine & cosine')  

ylim([-3 3])  

xlim([0 6])  

Output Results:

The first plot shows that sine wave gets shifted to upper side with respect to the original sine wave.

The second plot shows that the amplitude of the sine wave is increased with respect to the original sine wave.

The third plot shows that the frequency of the sine wave is increased. The number of cycles are increased with respect to the original sine wave.

The fourth plot shows there is a phase shift between two waves. The modified sine wave lags the original sine wave by π/4  

The fifth plot shows the relationship between sine and cosine wave.

As we know sin(2πt)=cos(2πt - π/2)

Therefore, both waves are superimposed on each other since they are equal.

3 0
3 years ago
Use Theorem 7.4.1. THEOREM 7.4.1 Derivatives of Transforms If F(s) = ℒ{f(t)} and n = 1, 2, 3, . . . , then ℒ{tnf(t)} = (−1)n dn
Ugo [173]

Answer:

L\left(te^{2t }sin3t\right)=\frac{6s-12}{(s^2-4s+13)^2}.

Step-by-step explanation:

If F(s)= L{f(t)}

Then L\left\{(t^nf(t)\right\}=(-1)^n\frac{\mathrm{d^n}F(s)}{\mathrm{d^n}s}

L\left\{te^{2t}sin3t\right\}

f(t)=e^{2t}sin3t

L\left\{e^{at}sinbt\right\}=\frac{b}{(s-a)^2+b^2}

Therefore,L\left\{e^{2t}sin3t\right\}=\frac{3}{(s-2)^2+(3)^2}

L\left\{e^{2t}sin3t\right\}=\frac{3}{s^2-4s+13}

L\left\{te^{2t}sin3t\right}=-\frac{\mathrm{d}F(s)}{\mathrm{d}s}

=-\frac{\mathrm{d}e^{2t}sin3t}{\mathrm{d}s}

L\left\{te^{2t}sin3t\right\}

=\frac{3(2s-4)}{(s^2-4s+13)^2}

L\left\{te^{2t}sin3t\right\}=\frac{6s-12}{(s^2-4s+13)^2}.

7 0
4 years ago
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