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3 years ago

How to solve and the answer

Mathematics

1 answer:

algol133 years ago

6 0

A reciprocal just flips the fraction

1. $\frac{4}{3}$

2. $\frac{11}{1}$

3. Before it is flipped it is $\frac{9}{1}$ but it turns into $\frac{1}{9}$

Hope this helps!

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AAAAAAAAA help please

Firdavs [7]

The answer is the first one BC ~ CD
Ok done. Thank to me:>

4 0

3 years ago

1. Adjacent angles are two angles in the same plane with a common

stepan [7]

Answer:

Adjacent angles are two angles in the same plane with a common VERTEX and a common SIDE but no common interior points.

Step-by-step explanation:

Adjacent angles share a common side on the same vertes, but they do not overlap each other.

In the attached image, ∠ABD is adjacent to ∠DBC, but ∠ABC is not adjacent to any of them.

4 0

3 years ago

9/20

Stella [2.4K]

Question:

Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0

Answer:

The number of real solutions for the equation $x^{2}+5 x+7=0$ is zero

Solution:

For a Quadratic Equation of form : $a x^{2}+b x+c=0$ ---- eqn 1

The solution is $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now , the given Quadratic Equation is $x^{2}+5 x+7=0$ ---- eqn 2

On comparing Equation (1) and Equation(2), we get

a = 1 , b = 5 and c = 7

In $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$ , $b^2 - 4ac$ is called the discriminant of the quadratic equation

Its value determines the nature of roots

Now, here are the rules with discriminants:

1) D > 0; there are 2 real solutions in the equation

2) D = 0; there is 1 real solution in the equation

3) D < 0; there are no real solutions in the equation

Now let solve for given equation

$D= b^2 - 4ac\\\\D = 5^2 - 4(1)(7)\\\\D = 25 - 28 \\\\D = -3$

Since -3 is less than 0, this means that there are 0 real solutions in this equation.

4 0

4 years ago

2. Cut and paste an example of an Undefined Slope?

viktelen [127]

Answer:

Ok here

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Please let me know the explanation of the the answer u will tell for this Question..

attashe74 [19]

$\huge \purple{\tt{Answer:}}$

Area of square = (length)²

$= \sf {(3{\dfrac{1}{2}})^2} \\\\\ = \sf {12.25~cm^2}$

$\sf{12{\dfrac{1}{4}}}$

7 0

3 years ago